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Marianna [84]
4 years ago
13

If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?

Chemistry
1 answer:
solmaris [256]4 years ago
5 0

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂  = 4.9kg  = 4900g

Unknown:

Number of molecules  = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

 Number of moles  = \frac{mass}{molar mass}

          Molar mass of CO₂  = 12 + 2(16)  = 44g/mol

   Number of moles  = \frac{4900}{44}  = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

       1 mole  = 6.02 x 10²³molecules

     111.36 moles  =   111.36 x 6.02 x 10²³molecules   = 6.7 x 10²⁶molecules

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7 0
3 years ago
A cup of coffee has 71 mL of coffee and 127 mL of water. What is the percent volume of the coffee solution?
Anna [14]

Answer:

35.9%

Explanation:

The percent volume of the coffee solution can be calculated as follows:

% volume of coffee solution = volume of coffee/total volume of coffee solution × 100

According to this question, a cup of coffee has 71 mL of coffee and 127 mL of water. This means that, the total volume of coffee solution is;

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3 years ago
Using the following thermochemical data, what is the change in enthalpy for the following reaction?
slavikrds [6]

Answer:

D. -120.9 kJ

Explanation:

According to Hess's law ,the total enthalpy change for a reaction is the sum of all changes regardless of the stages or the steps of the reaction.

CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = -186\ kJ)....(1)

CaO + H_{2}O\rightarrow Ca(OH)_{2}\ (\Delta H = - 65 \ kJ)

(this reaction should be reversed in order to reach the required reaction )

On reversing the reaction the sign of \Delta H get reversed.

(In this case change sign from '-' to'+'. Hence  \Delta H = + 65 kJ)

CaO + 2HCl \rightarrow  CaCl_{2} + H_{2}O\ (\Delta H = - 186\ kJ)....(1)

Ca(OH)_{2}   \rightarrow  CaO + H_{2}O\ (\Delta H = + 65 kJ )......(2)

Adding equation (1) and (2)

Ca(OH)_{2} + 2HCl \rightarrow CaCl_{2} + 2H_{2}O[tex][tex]Delta H = - 186 + 65 = - 121\kJ

Delta H = - 121\kJ (It is nearly equal to -120.9 kJ)

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3 years ago
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3 years ago
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Answer:

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Explanation:

8 0
4 years ago
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