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Marianna [84]
3 years ago
13

If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?

Chemistry
1 answer:
solmaris [256]3 years ago
5 0

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂  = 4.9kg  = 4900g

Unknown:

Number of molecules  = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

 Number of moles  = \frac{mass}{molar mass}

          Molar mass of CO₂  = 12 + 2(16)  = 44g/mol

   Number of moles  = \frac{4900}{44}  = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

       1 mole  = 6.02 x 10²³molecules

     111.36 moles  =   111.36 x 6.02 x 10²³molecules   = 6.7 x 10²⁶molecules

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Answer is: there are two compounds with molecular formula C₂H₆O, one alcohol and one ethar.

Alcohol with molecular formula C₂H₆O is ethanol or ethyl alcohol (C₂H₅OH).

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4 0
3 years ago
Read 2 more answers
How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
Vika [28.1K]

Answer:

Explanation:

we know that specific heat is the amount of heat required to raise the  temperature of substance by one degree mathmeticaly

Q=mcΔT

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ΔT=26.8-10.2=16.6

C for water is 4.184

therefore

Q=1.00*4.184*16.6

Q=69.4 j

now we have to covert joule into calorie

1 calorie =4.2 j

x calorie=69.4 j/2

so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius

6 0
2 years ago
When a 2 kg log is burned, it produces 0.5 kg of ash. Explain why the mass of the ash is less than the mass of the log. In other
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Answer:

my mass turned into gasses and other substances besides ash

Explanation:

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3 0
3 years ago
A stream leaving a mountain range deposits a large part of its load in a(n): alluvial fan sandbar meander sand dune
pshichka [43]

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3 0
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If 0.251moles of H2O gas are produced, how many liters of oxygen gas was used?
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Answer:

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Explanation:

hope this helps

4 0
3 years ago
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