Answer:
0.51 cal/g.°C
Explanation:
Step 1: Given data
- Added energy in the form of heat (Q): 14 cal
- Mass of the liquid (m): 12 g
- Initial temperature: 10.4 °C
- Final temperature: 12.7 °C
Step 2: Calculate the temperature change
ΔT = 12.7 °C - 10.4 °C = 2.3 °C
Step 3: Calculate the specific heat of the liquid (c)
We will use the following expression.
c = Q / m × ΔT
c = 14 cal / 12 g × 2.3 °C = 0.51 cal/g.°C
Answer:
T = 401.6 K
Explanation:
Given reaction:
The thermodynamic parameters; ΔG°, ΔH° and ΔS° are related via the Gibbs -Helmholtz equation given as:
For a given reaction, the gibbs free energy change ΔG° is related to the equilibrium constant K as:
It is given that K = 1,
Therefore,
Substituting for ΔG° in equation (1)
Answer:
0.64 m
Explanation:
Given that;
1L = 0.001 cubic metre
Then;
263 L = 263 L × 0.001 cubic metre/1L
= 0.263 cubic metre
Volume of a cube = l^3
l= 3√V
l= 3√0.263 cubic metre
l= 0.64 m
Explanation:
mass = no. of moles x molar mass (Mr)
i- mass = 10.2 mol x 30 g/mol
= 306 g
ii- mass of potassium hydroxide = 0.0146 mol x 56g/mol
= 0.8176g
mass of calcium hydroxide= 0.0146mol x 74 g/mol
= 1.0804g
Answer:
The answer to your question is Pressure = 3.55 atm
Explanation:
Data
R = 0.082 atm L/mol°K
mass = 4.5 g
volume = 2 L
temperature = 35°C
Pressure = ?
Process
1.- Calculate the moles of Methane
molar weight = 12 + 4 = 16 g
16 g of Methane --------------- 1 mol
4.5 g --------------- x
x = (4.5 x 1)/16
x = 0.281 moles
2.- Convert temperature to Kelvin
°K = 273 + 35
= 308
3.- Use the ideal gas law to solve this problem
PV = nRT
- Solve for P
P = nRT / V
- Substitution
P = (0.281)(0.082)(308) / 2
- Simplification
P = 7.097 / 2
- Result
P = 3.55 atm
