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stepan [7]
3 years ago
15

Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After

2 hours, they are 232 miles apart. What is the speed of each car? 52 mph; 64 mph 55 mph; 70 mph 92 mph; 104 mph 98 mph; 110 mph?
Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0
D = rt.  The first car's rate is r, and the other one, going faster, is r + 12.  The time they travel is 2 hours.  Since one is going faster than the other, he has gotten farther.  But, regardless of that, the distance between them is 232.  So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232.  2r + 2r + 24 = 232.  Solve for r.  4r = 208 and r = 52.  The slower one goes 52 and the faster one goes 64
Nutka1998 [239]3 years ago
7 0
The first cars speed is X miles per hour.
 The 2nd cars speed is X + 12 miles per hour

X + X +12 = 232 / 2

2x +12 = 116

2x = 116-12

2x = 104

x = 104 / 2
x = 52

x+12 = 52+12 = 64


 The 2 cars are driving 52 and 64 miles per hour


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8 0
3 years ago
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lara31 [8.8K]
Step One
Find z
All triangles have 180 degrees. No exceptions.
z + 47 + 90 = 180      combine like terms on the left.
z + 137 = 180            subtract 137 from both sides
z =  180 - 137        
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Step Two
Use the sine function to find y
Sin(43) = opposite side / hypotenuse
opposite side = 35 

sin(43) = 35 / hypotenuse
hypotenuse = 35 / sin(43)
y = 35/0.6820
y = 51.32 

Solve using cos(x)
Note this problem could have been done in a shorter way.
Cos(47) = adjacent / hypotenuse.
hypotenuse = adjacent / cos(47)
y = 35 / cos(47)
y = 35 / 0.6820
y = 51.32 Both answers agree. It is a good thing to know how to do this question both ways.
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4 0
3 years ago
Read 2 more answers
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