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Dmitry [639]
3 years ago
12

Please help me to answer this question

Mathematics
1 answer:
ikadub [295]3 years ago
5 0
(180-x) + 18 + 30 + x/2 = 180

=> 180 + 48 - x + x/2 = 180

=> -x/2 + 48 = 0

=> x/2 = 48

=> x = 48×2 = 96°
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Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?
Whitepunk [10]

Given:

Point is T(-3,8).

To find:

The coordinates of T' after R(y-axis)\circ R(x-axis).

Solution:

We know that, R(y-axis)\circ R(x-axis) means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

(x,y)\to (x,-y)

T(-3,8)\to T_1(-3,-8)

If a figure reflected across y-axis, then

(x,y)\to (-x,y)

T_1(-3,-8)\to T'(-(-3),-8)

T_1(-3,-8)\to T'(3,-8)

Therefore, the required point is T'(3,-8).

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Find the distance between the points (11, 4) and (10, 5).​
alexdok [17]

Answer:

square root of 2 or if needed simplified, 1.414213 to the nearest millionth.

Step-by-step explanation:

Start with the equation d= square root of (11-10)^2+(4-5)^2 where that is simplified to square root of (1)^2+(-1)^2 to square root of 1+1 to your final answer, square root of 2. Also simplified to 1.414213.

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Step-by-step explanation:

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x(4x

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3 years ago
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