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Dafna1 [17]
3 years ago
12

A total of 585 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 fewer stu

dent tickets sold than adult tickets. How many adult tickets were sold?
Mathematics
1 answer:
natulia [17]3 years ago
3 0

Answer:

325

Step-by-step explanation:

Total Tickets = 585

Let the adult tickets be = x

If 65 fewer student tickets were sold than adult tickets then Student tickets = x-65

Student Tickets + Adult Tickets = 585

x + (x-65) = 585

x + x - 65 = 585

2x - 65 = 585

2x = 585 + 65

2x = 650

2x/2 = 650/2

x = 325

Answered by Gauthmath

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Question 1123428: A bucket is in the shape of a truncated cone.The height of the bucket is 45 cm,and the diameters of the top and the bottom surfaces are 56 cm and 14 cm respectively.Find the the quantity (in litres) of the water the bucket can hold.

Answer by Boreal(9049) About Me  (Show Source):

You can put this solution on YOUR website!

V=(1/3)(r1^2+r1r2+r2^2)h*pi

=(1/3)*45*(28^2+196+49)*pi

=15(1029)*pi


A piece of paper is in the shape of a sector of a circle whose radius is 12 cm and the central angle of the sector is 120 degree.

It is rolled to form a cone of the biggest possible capacity.

Find the capacity of cone.

:

Find the total area of the sector

A = 120%2F360*pi%2A12%5E2

A = 150.8 sq/cm, this is surface area of the cone

:

Surface area (SA) of a cone without the end formula

The slant length (s) = the radius of the paper; 12 cm

pi%2Ar%2As+=+SA

pi%2Ar%2A12+=+150.8 , find r, the radius of the cone

r = 150.8%2F%2812%2Api%29

r = 4 cm is the radius

find the height of the cone

h = sqrt%28s%5E2-r%5E2%29

h = sqrt%2812%5E2-4%5E2%29

h = 11.3 cm is the height of the cone

Find the capacity (volume)

V+=+1%2F3*+pi%2Ar%5E2%2Ah

V = 1%2F3*pi%2A4%5E2%2A11.3

V = 189.33 cu/cm


6 0
3 years ago
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