Answer:
3966.82 J
Explanation:
q=sm∆T
q=73×13×4.18
the specific heat for water is 4.18
The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air.
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Answer:
84.75°C is the boiling point of water at an elevation of 7000 meter.
Explanation:
Rate of change of pressure = 19.8 mmHg/1000 ft
1 foot =
meter

Pressure change for every 1 m = 0.065 mmHg × 1= 0.065 mmHg
Elevation Pressure
0 m 760 mmHg
1000 m 695 mmHg
2000 m 630 mmHg
Pressure drop at the elevation of 7000 m: 
Pressure at 7000 m = 760 mmHg - 455mmHg = 305 mmHg
The boiling point of water decreases 0.05°C for every 1 mmHg drop in atmospheric pressure.
At 7000 meter elevation the boiling of water will be :

Boiling point of water at 7000 meter elevation :

84.75°C is the boiling point of water at an elevation of 7000 meter.
The percent error in the initial measurement would be 6.47%
<h3>Percent Error</h3>
Percent error in any measurement is mathematically given as:
absolute error/true measurement x 100%
In this case;
True measurement = 1.34 qt
Absolute Error = 1.34 - 1.25
= 0.09 qt
Percent error = 0.09/1.34 x 100%
= 6.47%
More on percent error can be found here: brainly.com/question/3105259?referrer=searchResults