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yKpoI14uk [10]
3 years ago
14

Anyoneeee know thissss!?

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

C. 3 and 4

Explanation:

Count H's in formula (each has 4)

- Hope that helped! Please let me know if you need a further explanation.

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What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?
scoundrel [369]

Answer:

b. Beta emission, beta emission

Explanation:

A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

8 0
2 years ago
The pipet used for transferring the pickle juice to the flask was dirty and consequentially some of the pickle juice stuck to th
lesya [120]

Explanation:

Since, some of the given sample is stuck inside and behind the pipet. Hence, there will occur a decrease in the percent of acetic acid.

This is because a decrease in concentration of the acid will also lead to a decrease in the amount of sample taken for the estimation. Since. lesser is the amount or concentration present lesser will be its analyte concentration.

For example, we took 10 mg of a pickel sample but 3 mg of the sample remain stuck in the pipet. This means we actually titrating a  sample less than 10 mg.

Therefore, the analyte concentration in the pickel will also be less.

6 0
3 years ago
How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl
VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3}  }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}

3 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 20.4 g g of carbon were burned in the presence
Aleonysh [2.5K]

Answer:

C + O2 -> CO2

C 20.4/12 = 1.7

O 70.4-16.0/16=3.4

CO2 1.7 mol * 44 = 74.8

3 0
3 years ago
Pls help!!! ILL GIVE BRAINLIEST, 70 points + 10 more if not plagiarized ty ty (also for those who scam and do it for the points
sukhopar [10]

Answer:

What procedure did you use to complete the lab?

→Procedures that needs to be considered to complete the lab are- a thorough knowledge of lab assignments, knowledge about safety equipment, reviewing the MSDS of chemicals for lab experiment etc.

<h3>Explanation:</h3>

To be lab prepared one must follow these procedures-

1. One should have the knowledge of lab assignments to make the lab experiment easier.

2. To be aware about safety equipment and their uses in lab, like- the location of fire extinguisher in lab.

3. To know the steps of experiments to be performed

4. To fill notebook of lab with information regarding the experiment

5. One should review the data sheets of chemicals material safety.

6. To put on all the necessary dressings to perform experiment.

7. To have complete understanding about the experiment disposals.

7 0
2 years ago
Read 2 more answers
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