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2 years ago

Describe the worlds outer core

2 answers:

7 0

Earth's outer core is a fluid layer about 2,400 km (1,500 mi) thick and composed of mostly iron and nickel that lies above Earth's solid inner core and below its mantle. Its outer boundary lies 2,890 km (1,800 mi) beneath Earth's surface. ... Unlike the inner (or solid) core, the outer core is liquid.

lina2011 [118]2 years ago

4 0

Answer:

MARK ME BRAINLIST

Explanation:T he outer core is the third layer of the Earth. It is the only liquid layer, and is mainly made up of the metals iron and nickel, as well as small amounts of other substances. The outer core is responsible for Earth’s magnetic field. As Earth spins on its axis, the iron inside the liquid outer core moves around.

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What is frequency? How can sound wave having different frequencies have the same speed

sashaice [31]

Answer:

The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw = fλ, where vw is the speed of sound, f is its frequency, and λ is its wavelength. ... The more rigid (or less compressible) the medium, the faster the speed of sound

Explanation:

8 0

2 years ago

Read 2 more answers

Please help me fast because I’m being timed!!

Sergio [31]

Answer:

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Explanation:

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3 years ago

Consider the reaction of metallic copper with iron(!!) to give copper(ll) and ironin 0.77V Fe* (aq) + e-Fe (aq) Cup (aq) + 2e --

frosja888 [35]

Answer :

(a) The anode and cathode will be $E^o_{(Cu^{2+}/Cu)}$

and $E^o_{(Fe^{3+}/Fe^{2+})}$ respectively.

(b) The emf of cell potential is 1.022 V

Explanation :

(a) The standard reduction potentials for iron and copper are:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

From the standard reduction potentials we conclude that, the substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

So, iron will undergo reduction reaction will get reduced. Copper will undergo oxidation reaction and will get oxidized.

The given cell reactions are:

Oxidation half reaction (anode): $Cu\rightarrow Cu^{2+}+2e^-$

Reduction half reaction (cathode): $Fe^{3+}+1e^-\rightarrow Fe^{2+}$

Thus, the anode and cathode will be $E^o_{(Cu^{2+}/Cu)}$

and $E^o_{(Fe^{3+}/Fe^{2+})}$ respectively.

(b) Now we have to calculate the potential of a cell.

Oxidation half reaction (anode): $Cu\rightarrow Cu^{2+}+2e^-$

Reduction half reaction (cathode): $Fe^{3+}+1e^-\rightarrow Fe^{2+}$

In order to balance that electrons, we will multiple the reduction reaction by 2, we get:

Oxidation half reaction (anode): $Cu\rightarrow Cu^{2+}+2e^-$

Reduction half reaction (cathode): $2Fe^{3+}+2e^-\rightarrow 2Fe^{2+}$

The overall cell reaction will be,

$2Fe^{3+}+Cu\rightarrow Cu^{2+}+2Fe^{2+}$

$E^o_{[Fe^{3+}/Fe^{2+}]}=2\times 0.77V=1.54V$

$E^o_{[Cu^{2+}/Cu]}=0.34V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o=E^o_{[Fe^{3+}/Fe^{2+}]}-E^o_{[Cu^{2+}/Cu]}$

$E^o=1.54V-(0.34V)=1.20V$

Now we have to calculate the cell potential.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]^2[Cu^{2+}]}{[Fe^{3+}]^2}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = emf of the cell = ?

Now put all the given values in the above equation, we get:

$E_{cell}=1.20-\frac{0.0592}{2}\log \frac{(0.20)^2(0.25)}{(0.0001)^2}$

$E_{cell}=1.022V$

Therefore, the emf of cell potential is 1.022 V

5 0

2 years ago

What is the balanced equation for the manufacture of ethanol from glucose

Darina [25.2K]

Answer:

C6H12O6 → 2C2H5OH + 2CO2

Explanation:

Glucose is an organic molecule, specifically a sugar, with the formula C612O6 while ethanol is another organic molecule with formula; C2H5OH.

However, as rightly said in this question, ethanol can be got from glucose via a process called fermentation in the presence of a catalyst called YEAST. The balanced equation is as follows:

C6H12O6 → 2C2H5OH + 2CO2

7 0

2 years ago

Change these word equations into formula equations and balance them. Be sure to use the proper symbols to indicate the state of

Ket [755]

Answer:

See detailed reaction equations below

Explanation:

a) Mg(s) +2HBr(aq) ----------------> MgBr2(aq) + H2(g)

b) Ca(ClO3)2(s) ------------> CaCl2(s) + 3O2(g)

c) 3BaBr2(s) +2Na3PO4(aq) ------------> Ba3(PO4)2(s) + 6NaBr(aq)

d) 3AgNO3(aq) + AlI3(aq) --------------> 3AgI(s) + Al(NO3)3(aq)

Balancing reaction equations involves taking valencies and number of atoms of each element on the reactants and products side into consideration respectively.

3 0

2 years ago