Answer:
Step-by-step explanation:
Corresponding scores before and after taking the course form matched pairs.
The data for the test are the differences between the scores before and after taking the course.
μd = scores before taking the course minus scores before taking the course.
a) For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.
Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.
c) The mean difference for the sample scores is greater than or equal to zero
Hey there,
solving for a is just like you think of all other letter as a constant
i.e the only variable is a
so you need to subtract b as a start
d=a+b-c/3
-b -b
=============
-b+d=a-c/3 now it's time to add c/3 (isolate a by itself in one side)
-b+d=a-c/3
+c/3 +c/3
==============
c/3-b+d=a
Hence you have solved for a
Answer: 0.395 km
Step-by-step explanation:
Let Martin distance from the hole be X
On first stroke, his golf ball traveled 4/5 of the distance to the hole. That is 4/5 X
On his second stroke, the ball traveled 79 meters and went into the hole
Total distance covered will be
X = 79 + 4/5X
X - 4/5X = 79
X - 0.8X = 79
0.2X = 79
X = 79/0.2 = 395 meters
How many kilometers from the hole was Martin when he started
X = 395/1000 = 0.395 km
32*1.2=38.4 (.2 is the 20%, and the 1 adds the percent to the original cost making it a mark up)
Answer:
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Step-by-step explanation:
