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d1i1m1o1n [39]
3 years ago
6

Keisha the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the

other (not both). On Wednesday there were 2 clients who did Plan A and 3 who did Plan B. On Thursday there were 6 clients who did Plan A and 5 who did Plan B. Keisha trained her Wednesday clients for a total of 6 hours and her Thursday clients for a total of 12 hours. How long does each of the workout plans last?
Mathematics
1 answer:
gregori [183]3 years ago
6 0

Answer:

Plan A last 0.75 hours or 45 minutes.

Plan B last 1.5 hours or 90 minutes.

Step-by-step explanation:

Let a be the number of hours that the plan A last, an b the number of hours of plan B. Then for the Wednesday you have:

2a+3b=6

And for the Thursday is:

6a+5b=12

Multiply the equation of Wednesday by -3:

-6a-9b=-18

Using the method of addition using this last equation and the equation of Thursday

-6a-9b=-18\\6a+5b=12\\--------\\-4b=-6\\b=\frac{-6}{-4}\\b=1.5 hours

Replacing the value of b in one of the equations

6a+5b=12\\6a+5(1.5)=12\\6a+7.5=12\\6a=12-7.5\\a=\frac{4.5}{6} \\a=0.75hours

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You can simply expand each product and see whether it gives you a difference of squares.


•  \mathsf{(-7x+4)\cdot (-7x+4)}

That's actually  \mathsf{(-7x+4)^2:}

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     \mathsf{=49x^2-56x+16}        <span>✖

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</span>————<span>—

</span>•  \mathsf{(-7x+4)\cdot (4-7x)}

     \mathsf{=(-7x+4)\cdot 4-(-7x+4)\cdot 7x}\\\\ \mathsf{=-28x+16-(-49x^2+28x)}\\\\ \mathsf{=-28x+16+49x^2-28x}

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which is not a difference of squares.

—————

•  \mathsf{(-7x+4)\cdot (-7x-4)}

     \mathsf{=(-7x+4)\cdot (-7x)-(-7x+4)\cdot 4}\\\\ \mathsf{=49x^2-28x-(-28x+16)}\\\\ \mathsf{=49x^2-\diagup\!\!\!\!\! 28x+\diagup\!\!\!\!\! 28x-16}\\\\ \mathsf{=49x^2-16}

     \mathsf{=(7x)^2-4^2}        <span>✔

That is a difference of two squares.

</span>————<span>—

</span>•  \mathsf{(-7x+4)\cdot (7x-4)}

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     \mathsf{=-49x^2+56x-16}        <span>✖

</span>which is not a difference of squares.

—————

Only the  third option  will result in a difference of squares.


Answer:  (− 7x + 4) · (− 7x − 4).


I hope this helps. =)

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