Answer:
523.3 cubic inches
Step-by-step explanation:
A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?
The shape of a basketball is spherical.
Hence:
The volume of a basketball = 4/3 × π × r³
From the question,
π = 3.14
r = radius = Diameter/2
r = 10 in/2 = 5 in
Hence:
The volume of the basketball
= 4/3 × 3.14 × 5³
= 1570 ÷ 3
= 523.33333333 cubic inches
Therefore, the approximate volume of the basketball = 523.3 cubic inches
Elemantary school so
area=legnth times width
to get greatest area, make legnth as close to width as possible in measure
to get least area, make legnth as far away from width as possible in measure
perimiter=2 times legnth+2 times width=2 times (legnth+width)
18=2 times (legnth+width)
divide 2
9=legnth+width
find closest and farthest
1+9 is farthest
4+5 is closest
areas=legnth times with
1 times 9=9
4 times 5=20
differnce is subtract
20-9=11
answe is 11
(note I didn't use decimals since the user is supposedly in elemenatry school)
Answer:
y=2x+0 or y=2x
Step-by-step explanation:
y=mx+b
m=2
b=0
Answer:
Step-by-step explanation:
Volume of the cuboid = Length * Width * Height
Given
Length = 4cm
Width = (x+1)cm
Height = (x-11)cm
Volume of the cuboid = 4(x+1)(x+11)
Volume of the cuboid = 4(x^2+11x+x+11)
Volume of the cuboid = 4(x^2+12x+11)
Volume of the cuboid = 4x*2+48x+44
925 = 4x*2+48x+44
4x*2+48x+44-925 = 0
4x*2+48x-881 = 0
Divide through by 4
x^2 + 12x - 220.25 = 0
Factorize using the general formula;
x = -12±√12²-4(-220.25)/2
x = -12±√144+881/2
x = -12±√1025/2
x = -12±32/2
x = 12+32/2
x = 20/2
x = 10
Hence the dimension of the cuboid is 4cm, (10+1)cm and (10+11)cm
Dimension is 4cm by 11cm by 21cm
♦Which figure has all sides of equal measure but not necessary all angles of equal measure?
Ans: H. Rhombus.
♦Which shape must have opposite sides that are parallel and congruent, and diagonals that are perpendicular bisectors of each other?
Ans: A) Parallelogram.
♦In rectangle ABCD, the slope of.........
Ans: 1/2
Ans:
