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Fed [463]
3 years ago
11

If z = (5 + 12i) ÷ (3 + 4i), then |z| = _____. 5/13 1(2/3) 2(3/5) 3

Mathematics
2 answers:
Maurinko [17]3 years ago
6 0

Answer:

i have the answer

Step-by-step explanation:

the correct answer is 2 and three fifths. good luck

Marta_Voda [28]3 years ago
3 0
\dfrac{5+12i}{3+4i}=\dfrac{5+12i}{3+4i}\cdot\dfrac{3-4i}{3-4i}=\dfrac{15-20i+36i-49i^2}{3^2-(4i)^2}\\\\=\dfrac{15+16i+49}{9-16i^2}=\dfrac{64+16i}{9+16}=\dfrac{64+16i}{25}=2.56+0.64i


z=a+bi\\\\|z|=\sqrt{a^2+b^2}\\\\z=2.56+0.64i\to a=2.56;\ b=0.64\\\\|z|=\sqrt{2.56^2+0.64^2}=\sqrt{6.9632}=\sqrt{\dfrac{69632}{10000}}=\sqrt{\dfrac{4096\cdot17}{100}}\\\\=\dfrac{64\sqrt{17}}{100}=0.64\sqrt{17}\approx2.6=2\dfrac{3}{5}
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cestrela7 [59]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Solve the equation <img src="https://tex.z-dn.net/?f=8x%5E2%3D-36" id="TexFormula1" title="8x^2=-36" alt="8x^2=-36" align="absmi
chubhunter [2.5K]

Answer: 4(2x²+9) or i\frac{3\sqrt{2} }{2}

Step-by-step explanation:

To solve the equation by factoring, we want to set the equation to zero. In order to have the equation equal to zero, we want to add both sides by 36.

8x²=-36            [add both sides by 36]

8x²+36=0

When it comes to factoring, we want to pull out numbers or variables that are common in each term.

8x²+36=0         [take out a 4 in each term]

4(2x²+9)=0

It may seem that 2x²+9 can be factored further, it actually can't. This tells us that the factored form of the equation is 4(2x²+9)=0.

To solve the equation, we want to find the value of x. We already know the graph does not cross the x-axis because the y-intercept or vertex is (0,9).

4(2x²+9)=0       [divide both sides by 4]

2x²+9=0            [subtract both sides by 9]

2x²=-9               [divide both sides by 2]

x²=-9/2              [square root both sides]

x=\sqrt{-\frac{9}{2} } or x=i\frac{3\sqrt{2} }{2}

6 0
3 years ago
Read 2 more answers
How do i solve x/2+1/3=x/3+1/2
stepladder [879]
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x/2=x/3+1/2-1/3
x/2 - x/3 = 3/6 - 2/6
x/2 - x/3 = 1/6
3x/6 - 2x/6 = 1/6
x/6 = 1/6
x = 1/6 * 6

x = 1

8 0
3 years ago
Read 2 more answers
find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).​
maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).​

To find:

The component equation of the plane.

Solution:

The equation of plane is

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Where, (x_0,y_0,z_0) is the point on the plane and \left< a,b,c\right> is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

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-2x+5y+z-60=0

-2x+5y+z=60

Therefore, the equation of the plane is -2x+5y+z=60.

4 0
3 years ago
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jolli1 [7]
30 mins = 180°
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hope this helps you

5 0
3 years ago
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