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Charra [1.4K]
3 years ago
14

(x^2-5x+6)+(3x^2-8x-2)

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

4x^2-13x+4

Step-by-step explanation:

1. Add together all like terms ( so x^2+3x^2=4x^2)

2. once you add all your like terms. order the numbers from biggest to smallest (4x^2'-13x+4)

*You'll know which is biggest by the exponent!

Hope this helps!!!!!

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F is between E and G. EF=3X, EG= 11x-2, FG= 5x+16. Find the value of the variable
Salsk061 [2.6K]

9514 1404 393

Answer:

  x = 6

Step-by-step explanation:

The sum of segments is used:

  EF +FG = EG

  3x +(5x +16) = 11x -2 . . . . substitute given expressions

  8x +18 = 11x . . . . . . . . add 2

  18 = 3x . . . . . . . . subtract 8x

  6 = x . . . . . . divide by 3

The value of the variable is 6.

__

<em>Check</em>

The segment lengths are ...

  EF = 3x = 3·6 = 18

  FG = 5x+16 = 5·6 +16 = 46

  EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct

3 0
3 years ago
Can anyone help me with my homework
eimsori [14]
1- B
2- G
3- H
4- A

I hope its good for you
3 0
3 years ago
© Find the LCM of 220 and 88.
Morgarella [4.7K]

Answer:

440

Step-by-step explanation:

multiple of 220

220, 440

multiple of 88

88, 176, 264, 352, 440

7 0
3 years ago
Find the 75th term of the following6, 10, 14, 18,
enot [183]

Given the sequence:

6, 10, 14, 18,...

We will find the 75th term

The given sequence is an arithmetic sequence

Because there is a constant common differnce

d = 18 - 14 = 14 - 10 = 10 - 6 = 4

The first term = a = 6

The general formula of the arithmetic sequence is as follows:

a_n=a+d(n-1)

Where: n is the nth term

To find the 75th term, substitute with n = 75 and a = 6, d = 4

a_{75}=6+4\cdot(75-1)=302

So, the answer will be the 75th term = 302

7 0
1 year ago
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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