the slope is y = 7/8x - 0.5 im pretty sure
Answer:
Table a match with Graph 3
Table b match with Graph 2
Table c match with Graph 4
Step-by-step explanation:
<u>Table a</u>
Time is plotted on x - axis and Temp on y axis
From table a we can see that the y values(temp) decrease with increasing time. The only graph that has a decreasing trend is Graph 3
<u>Table b</u>
Time plotted on x axis, cost on y axis
Looking at the values we see that they are almost linear except for 2 values at x = 2 and 2.5 and at y = 5 and 5.3.
Ignoring values 2.5 and 5.3 we see a linear fit with a slope of 20. This means either graph 1 or graph 2
However, the graph passes through (0,0) and this is not a set of values in the table. That leaves graph 2
<u>Table c</u>
Months plotted on x axis and length of fetus on the y axis
We can see that the y values (the length) increases slowly at lower values of x(x=1 and x=2) and then increase rapidly at the mid values(x = 2 thru 6) and then slows down between months 6 and 9. Only Graph 4 fits this pattern
There is another equation to solve it simultaneously
Answer:i think d.please dont blame me im not sure.sorry
Step-by-step explanation:
Answer:
present value = $16750
Step-by-step explanation:
The simple interest formula allows us to calculate A, which is the final amount. According to this formula, the amount is given by A = P (1 + r*t), where P is the principal, r is the annual interest rate in decimal form, and t is the loan period expressed in years
simple interest formula:
t: time
P: present value
A: amount
r
: anual interest
A = P (1 + r*t)
P = A / (1 + r*t)
P = 19,513.75 / (1 + 3/100 * 5.5)
P = 19,513.75/ (1 + 0.165)
P = 19,513.75 / 1.165
P = 16750
present value = $16750
