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Vlada [557]
3 years ago
5

Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. 3-i, squ

are root of 7
Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0
Real coefients
if a+bi is a root then a-bi is also a root
since 3-i is a root then 3+i s also a root

also the √7, so if √7 is a root then -√7 is also a root
so

f roots are r1 and r2 then the factored form is
f(x)=(x-r1)(x-r2)

roots are 3-i, 3+i and √7 and -√7

f(x)=(x-(3-i))(x-(3+i))(x-√7)(x-(-√7))
expanded
f(x)=x⁴-6x³+3x²+42x-70
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Answer:

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Step-by-step explanation:

7x + 2y = 7

-14x + 2y = -11

1) 7x + 2y = 7

2y = 7 - 7x

2) -14x + 2y = -11

-14x + 7 - 7x = -11

- 21x = -11-7

- 21x = - 18

x = 18/21 = 6/7

3) 2y = 7 - 7x = 7 - 7*(6/7) = 7 - 6 = 1

2y = 1

y = 1/2

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