Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. 3-i, squ
are root of 7
1 answer:
Real coefients
if a+bi is a root then a-bi is also a root
since 3-i is a root then 3+i s also a root
also the √7, so if √7 is a root then -√7 is also a root
so
f roots are r1 and r2 then the factored form is
f(x)=(x-r1)(x-r2)
roots are 3-i, 3+i and √7 and -√7
f(x)=(x-(3-i))(x-(3+i))(x-√7)(x-(-√7))
expanded
f(x)=x⁴-6x³+3x²+42x-70
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its the first 1. b.
Step-by-step explanation:
nb. b. b b b bcbcbc
C. Action: Divide both sides by 3.
Answer:
Step-by-step explanation:
3 over 2/3 → 3/1 divided by 2/3 → 3/1 x 3/2 (do keep change flip)
once you multiply you'll get 9/2.
Long Piece: x + 18
Short Piece: x
(x) + (x + 18) = 84
2x + 18 = 84
2x = 66
x = 33
Long Piece: x + 18 = (33) + 18 = 51
Answer: 33 meters and 51 meters
Per means divide. So..
Step 1. Find ur equation. 63\3
Step 2. Solve ur equation. 63\3 = 21
I think thats right.