6. What is the value of

Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)

Sati [7]

Answer:

(2,1)

Step-by-step explanation:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)$

8 0

3 years ago

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Its a word problem in algebra 1 that i need help on step by step ?

Luden [163]

Answer:

Cost of one rose bush = $2 and cost of 1 geranium = $11

Step-by-step explanation:

lets assume cost of one rose bush = $x

lets assume cost of one geranium = $y

Given that Norachai spent $13 on 1 rose and 1 geranium

⇒ 1 × (cost of one rose bush) + 1× (cost of one geranium) = 13

⇒ 1x + 1y = 13 ----------------------------equation 1

Also given that Castel spent $46 on 1 rose bush and 4 geraniums

⇒1 × (cost of one rose bush) + 4× (cost of one geranium) = 46

⇒ 1x + 4y = 46 ----------------------------equation 2

Now we are having following two equations which will be used to find the value of x and y

1x + 1y = 13 ----------------------------equation 1

1x + 4y = 46 ----------------------------equation 2

lets modify equation 1 to get value of y in terms of x and name that equation as equation 3

1x + 1y = 13 ----------------------------equation 1

⇒ y = 13 - x -----------------------------equation 3

On substituting value of y from equation 3 in equation 2 we get

1x + 4 × ( 13 - x ) = 46

⇒ x + 52-4x =46

⇒ -3x = 46-52

⇒ x = (-6)/(-3) = 2

on substituting calculated value of x that is 2 in equation 3 we get

y = 13 -2 = 11

so on solving the equations we get x = 2 and y = 11.

Hence cost of 1 rose bush = $x = $2 and cost of 1 geranium = $y = $11

8 0

2 years ago

Exercises<br />Part 2<br />Calculator<br />by justifying the measurement of angles: CAD and CDA<br />&lt

Diano4ka-milaya [45]

Answer:

yea

Step-by-step explanation:

3 0

2 years ago

Will mark BRAINLIEST to correct answer! Please help, this has to be correct. Thanks!

pogonyaev

The answer would be 314.16 square cm
Hope this helps! :)

4 0

3 years ago

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The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

3 years ago