The distance walked by Larry is 9 miles and Camille is 18 miles and Simone is 7 miles
<em><u>Solution:</u></em>
Let "x" be the distance walked by Larry
Let "y" be the distance walked by Camille
Let "z" be the distance walked by Simone
<em><u>At the end of the week they combined their distances and found that they walked 34 miles in total</u></em>
Total distance = 34 miles
Therefore, we can say,
x + y + z = 34 ---------- eqn 1
<em><u>Camille walked twice as far as Larry</u></em>
distance walked by Camille = 2(distance walked by Larry)
y = 2x ---------- eqn 2
<em><u>Larry walked 2 more miles than Simone</u></em>
distance walked by Larry = 2 + distance walked by Simone
x = 2 + z
z = x - 2 ------- eqn 3
<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>
x + 2x + x - 2 = 34
4x - 2 = 34
4x = 34 + 2
4x = 36
<h3>x = 9</h3>
<em><u>Substitute x = 9 in eqn 2</u></em>
y = 2(9) = 18
<h3>y = 18</h3>
<em><u>Substitute x = 9 in eqn 3</u></em>
z = 9 - 2
<h3>z = 7</h3>
Thus distance walked by Larry is 9 miles and Camille is 18 miles and Simone is 7 miles
