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Mila [183]
3 years ago
9

A family has two cars. the first car has a fuel efficiency of 25 miles per gallon of gas and the second has a fuel efficiency of

40 miles per gallon of gas. during one particular week, the two cars went a combined total of 1800 miles, for a total gas consumption of 60 gallons. how many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
Sedbober [7]3 years ago
3 0
1 ANSWER<span><span>Michael J.East Elmhurst, NY</span>1 0</span>Let x = gallons consumed by car 1Let y = gallons consumed by car 2  We set up our equations: 35x+40y = 1850        eq1x+y = 50                   eq2 Substituting eq 2 into eq 1, 35x+40(50-x) = 185035x+2000-40x = 1850-5x+2000 = 1850-5x = -150   x = 30 Substitute value of x into eq 2. x+y = 5030+y = 50      y = 20 Car 1 consumes 30 gallons of gas.Car 2 consumes 20 gallons of gas
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Answer:

Step-by-step explanation:

From the information given, we would write the hypothesis.

For the null hypothesis,

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For the null hypothesis,

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The decision rule is to reject the null hypothesis if the level of significance is greater than the p value and accept the null hypothesis if the level of significance is lesser than the p value.

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The data given below contain the state cigarette tax​ (in $) for all 20 regions of a country.
g100num [7]

Answer:

(a) \bar x= 1.583 -- Population Mean

(b) s = 1.032 --- Population standard deviation

(c) See Explanation

Step-by-step explanation:

Given:

Cigarette tax for 20 regions

Solving (a): The population mean

This is calculated as:

\bar x = \frac{\sum x}{n}

\sum x = 1.36 + 1.70 + 2.50 + 0.45 + 1.18 + 0.64 + 3.46 + 0.57 + 2.00 + 0.80 + 1.60 +0.98 + 0.36 + 2.24 + 4.35 + 0.62 + 2.70 + 1.78 + 1.53 + 0.84

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So, we have:

\bar x= \frac{31.66}{20}

\bar x= 1.583

Solving (b): The population standard deviation

This is calculated as:

s = \sqrt{\frac{\sum( x - \bar x)^2}{n}

\sum (x -\bar x)^2 = (1.36 - 1.583)^2 + (1.70 - 1.583)^2+ (2.50 - 1.583)^2+ (0.45 - 1.583)^2+ (1.18 - 1.583)^2+ (0.64 - 1.583)^2+ (3.46 - 1.583)^2+ (0.57 - 1.583)^2+ (2.00 - 1.583)^2+ (0.80 - 1.583)^2+ (1.60 - 1.583)^2+(0.98 - 1.583)^2+ (0.36 - 1.583)^2+ (2.24 - 1.583)^2+ (4.35 - 1.583)^2+ (0.62 - 1.583)^2+ (2.70 - 1.583)^2+ (1.78 - 1.583)^2+ (1.53 - 1.583)^2+ (0.84- 1.583)^2

\sum (x -\bar x)^2 = 21.29222

So:

s = \sqrt{\frac{21.2922}{20}

s = \sqrt{1.06461}

s = 1.032

Solving (c):

Population mean tells the average amount while the standard deviation represents the spread from the calculated mean

Option (4) is correct

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Answer:

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