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zhenek [66]
3 years ago
12

Find the derivative of y= (3x –1) 2with respect to x.​

Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

dy/dx = 18x – 6

Step-by-step explanation:

y = (3x – 1)²

Take derivative using power rule and chain rule:

dy/dx = 2 (3x – 1) × 3

dy/dx = 6 (3x – 1)

dy/dx = 18x – 6

You can check this answer by simplifying y before taking the derivative.

y = 9x² – 6x + 1

dy/dx = 18x – 6

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Simplify this equation<br> -5x+7&gt;22
Lana71 [14]

Answer:

<h2>x < - 3</h2>

Step-by-step explanation:

- 5x + 7 > 22

Move 7 to the other side of the inequality

- 5x > 22 - 7 \\  - 5x > 15

Divide both sides by - 5

\frac{ - 5x}{5}  >  -  \frac{15}{5}  \\ x >  - 3

Reverse the sign

We have the final answer as

<h3>x < - 3</h3>

Hope this helps you

4 0
2 years ago
Jessica and Maria got to the supermarket to buy fruit. Jessica
Burka [1]

Answer:$0.25 per apple

$0.30 per orange

Step-by-step explanation:

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3 0
2 years ago
1/3 x 8 in simplest form
makvit [3.9K]

In mathematics, every integer is a rational number, hence a whole number 8 can be written as 8/1. 1/3 x 8 = 8/3 in fraction form. 1/3 x 8 = 2.6667 in decimal form.

7 0
2 years ago
Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con
monitta

Let f(x)=e^{-1/x}. Then f'(x)=\frac1{x^2}e^{-1/x}>0 for all x\ge2, so f is strictly increasing. As x\to\infty, e^{-1/x}\to e^0=1, so f is bounded above by 1. This is to say,

e^{-1/x}

and the integral of \frac1{x^2} converges over the same domain, so this integral must also converge by comparison.

We have, by setting y=-\frac1x,

\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}

8 0
2 years ago
Find the length of a to the nearest tenth using the Pythagorean theorem
Leona [35]

Answer:

Ab^2 = CA^2 + BC^2

8^2 = 6^2 + a^2

64 = 36 + a^2

64-36 = a^2

28 = a^2

square root of 28 = square root of a^2

5 ,29 = a

5 = a

8 0
2 years ago
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