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3 years ago

A number increased by two thirds of the number

Mathematics

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

not sure if you're looking for an example of this or not but if you are then it could be something like 12 + 8 because 2/3 of 12 is 8.

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The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter

AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that $\mu = 7$

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052$

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

$P(X < 3) + P(X \geq 3) = 1$

We want $P(X \geq 3)$ , which is

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001$

$P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006$

$P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022$

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971$

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

$\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25$

5.25 people are expected to arrive during a 45-min period

5 0

3 years ago

Help please.

maria [59]

A1=-15
a2=a1+d→-4=-15+d→d=11

8 0

3 years ago

A motorboat heads upstream a distance of 24 miles on a river whose current is running at 3 miles per hour. The trip up and back

Kryger [21]

To get speed you do Distance/Time.

6 0

3 years ago

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Consider the following expression and determine which statements are true. m+(5n)(9-p)-6-r^2

Fed [463]

Answer:

(B)The expression (5n)(9-p) is the product

(D)The expression 9-p has exactly two terms

Step-by-step explanation:

In the expression;

$m+(5n)(9-p)-6-r^2$

The coefficient of m is 1, therefore Option A is not true

The product of 5n and 9-p is (5n)(9-p), therefore Option B is true.

The expression 9-p has exactly two terms,9 and p.

Therefore, Options B and D are true.

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3 years ago

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Who's faster a dog or a fish plz help me

VashaNatasha [74]

Answer:

fish

Step-by-step explanation:

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3 years ago

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