Sector area = (central angle / 360) * PI * radius^2
sector area = (72 / 360) * PI * radius^2
radius^2 = sector area / [(72 / 360) * PI]
radius^2 = 16.2 * PI / [(1 / 5) * PI]
radius^2 = 16.2 / .2
radius^2 = 81
radius = 9
Source:
http://www.1728.org/radians.htm
Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.
Answer:
Below in bold.
Step-by-step explanation:
Area = 30 + 12x and area is also = to width * length so we need to look for factors of 30 + 12x.
30 + 12x = 6(5 + 2x)
So 6 and 5 + 2x is one possible answer.
3 and 10 + 4x is another.
12 and 2.5 + x is another.
If we multiply these pairs together we see that the result is
30 + 12x in each case.
Answer:
-5
Step-by-step explanation:
f(-2) means that -2 is going to be our input in this function.
To solve this, simply substitute -2 for x in the expression given.
If f(x) = 3x+1, then f(-2) = 3(-2) + 1
3(-2)+1 = -6+1 = -5
Hope this helped!
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hope that helps !
