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zvonat [6]
4 years ago
6

Find the probability that at least one molecule in the breath you just took was shared with caesar’s last breath, and give a sim

ple approximation in terms of
e.
Mathematics
1 answer:
Alika [10]4 years ago
6 0

<span>Let </span>N<span><span>= 10^</span><span>44 </span><span>and </span>n</span><span><span>= 10^</span>22</span>.

 

Each molecule that we breathed in has probability (N-n)<span><span>/N </span><span>of not being from Caesar’s last breath. Also, the molecules breathed in are independent if it is assumed that sampling with replacement is performed. So the probability of at least one molecule being shared with Caesar’s last breath is:</span></span>

<span> 1</span><span><span>-[</span>(</span>N-n<span><span>)^</span><span>n/</span><span>N^</span><span>n] </span>= </span>

= 1-[(10^44-10^22)^(10^22) / 10^44^(10^22)]

Simplifying will result in:

= 1- (1/e)

 

<span>This is about a 63% chance!</span>

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3 years ago
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6 0
4 years ago
Can someone help me with this!! I’ve been stuck for awhile!!
scoundrel [369]

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3 0
3 years ago
PLEASE ANSWER THESE 2 QUESTIONS ASAP
Alik [6]
52-4= 48
48 card left so
48/52 is the probability. but you can't stop there, you need to reduce.
12/13 is the simplest form and so there is your probability. (divided by 4 to get it)
3 0
3 years ago
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