Answer:
155
Step-by-step explanation:
The problem sounds complicated, but it's not. Let's analyse.
The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.
We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.
Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).
In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.
y= 11x + 12
=> In Tracy's case: y= 11*13 + 12= 155
So the number of retail stores there were in 2003 was 155
Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
Answer: Step by step
Step-by-step explanation:
