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slega [8]
3 years ago
6

Oliver is thinking of a number. He multiplies it by 5, subtracts 26, and then divides by 6. He then multiplies his original numb

er by 3, and gets the same answer. Find Oliver's number.
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

Let Oliver's number be x.

He multiplies it by 5:

x * 5 = 5x

He then subtracts 26:

5x - 26

Then, he divides by 6:

\frac{5x - 26}{6}  

He then multiplies his original number by 3, and gets the same answer.

This implies that:

\frac{5x - 26}{6} = 3x

Let us simplify this:

\frac{5x - 26}{6} = 3x\\\\5x - 26 = 3x * 6\\\\5x - 26 = 18x

Collecting like terms:

5x - 18x = 26\\\\-13x = 26\\\\=> x = \frac{26}{-13}\\\\x = -2

Oliver's number is -2.

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1

144

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2 years ago
In how many ways can a committee of five women and four men be formed from a group of seven women and seven men?
vekshin1
Number of combinations of 5 women from 7  = 7C5 =  7*6 / 2 = 21
for men its 7C4  = 7*6*5 / 3*2 =  35

Total number of ways = 21*35  = 735
6 0
3 years ago
3 2/3 divided by 2 2/3
Goshia [24]

Answer:

1 3/8

Step-by-step explanation:

3 2/3 = 11/3

2 2/3 = 8/3

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5 0
3 years ago
Read 2 more answers
Need help pleaseee i have a test on friday
larisa [96]

Answer:

x = 8

Step-by-step explanation:

Using the sine or cosine ratio in the right triangle and the exact value

sin30° = \frac{1}{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{4}{x} = \frac{1}{2} ( cross- multiply )

x = 8

5 0
3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
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