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PtichkaEL [24]
3 years ago
5

A student takes the same street from his home to the university every day. There are 3 streetlights along the way, and he has no

ticed the following Markov dependence. If he sees a green light at an intersection, then 77% of time the next light is also green. However, if he sees a red light, then 77% of time the next light is also red. (Assume the chance of him seeing a yellow light is zero.) If the first light is green, what is the probability that the third light is red
Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

0.3542 = 35.42% probability that the third light is red

Step-by-step explanation:

For each light:

If it is green, 77% probability that the next is green.

If it is red, 77% probability that the next is red.

If the first light is green, what is the probability that the third light is red?

These following outcomes are desired, for the second and third lights:

G - R(0.77, then 1 - 0.77 = 0.23 probability)

R - R(0.23, then 0.77 probability).

So the desired probability is:

p = 0.77*0.23 + 0.23*0.77 = 0.3542

0.3542 = 35.42% probability that the third light is red

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Answer:

6 units away from 0.

Step-by-step explanation:

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3 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

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(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

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There are 27 girls and 36 boys who want to participate in a math competition. If each team must have the same ratio of girls and
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Since the ratio of girls and boys must be the same in each team, and all the competitors must be involved, it means that each team's ratio of boys : girls must be equal to the total ratio of Boys : Girls = 36 :27= 4 / 3.

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The formula for the volume of a cone is V = r²h, where r is the radius of the
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Answer:

<u>h = V/r²</u>

Step-by-step explanation:

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Solving :

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Answer:

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