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Sunny_sXe [5.5K]
3 years ago
14

How do you find the difference between 6/8 - 1/7

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:to find the difference between 6/8 and 1/7, you need to make the denominators (the bottom numbers) the same. turn 6/8 into 42/56. then turn 1/7 into 8/56. you’ll then do 42/56-8/56. so it’ll be 42-8=36. so it will come out to 36/56, which is (when simplified) is 9/14. your answer will be 9/14.

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Evaluate.
vesna_86 [32]

Answer:   B) 46

<u>Step-by-step explanation:</u>

We are looking for the sum of terms 2 through 5.  One option is to find each term and then add them up.

a_i=3i+1\\\\a_2=3(2)+1=7\\a_3=3(3)+1=10\\a_4=3(4)+1=13\\a_5=\underline{3(5)+1=16\ }\\.\qquad \quad \text{Total}=\boxed{46}

3 0
3 years ago
Find the perimeter of the figure. You must show all your work to receive full credit
Usimov [2.4K]

Answer:

32.2 units

Step-by-step explanation:

The perimeter of the figure = AB + BC + CD + DE + EF + FA

AB = |5 - 11| = 6 units

BC = |-8 - 0| = 8 units

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(11, 0) = (x_1, y_1)

D(6, -3) = (x_2, y_2)

CD = \sqrt{(6 - 11)^2 + (-3 - 0)^2}

CD = \sqrt{(-5)^2 + (-3)^2}

CD = \sqrt{25 + 9} = \sqrt{34}

CD = 5.8 units (nearest tenth)

DE = |6 - 4| = 2 units

EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

E(4, -3) = (x_1, y_1)

F(0, -6) = (x_2, y_2)

EF = \sqrt{(0 - 4)^2 + (-6 -(-3))^2}

EF = \sqrt{(-4)^2 + (-3)^2}

EF = \sqrt{16 + 9} = \sqrt{25}

EF = 5 units

FA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

F(0, -6) = (x_1, y_1)

A(5, -8) = (x_2, y_2)

FA = \sqrt{(5 - 0)^2 + (-8 -(-6))^2}

FA = \sqrt{(5)^2 + (-2)^2}

FA = \sqrt{25 + 4} = \sqrt{29}

FA = 5.4 units (nearest tenth)

Perimeter = 6 + 8 + 5.8 + 2 + 5 + 5.4

= 32.2 units

7 0
3 years ago
Given z1 and z2 below. Calculate z1/z2 and write your answer in rcistheta form.
andre [41]

Answer:

  (2/9)cis(30°)

Step-by-step explanation:

We can express the two numbers in magnitude∠angle form, then find their ratio.

  |z1| = 3√((-1)² +(√3)²) = 3√4 = 6

  ∠z1 = arctan((3√3)/(-3)) = -arctan(√3) = 120°

  z2 = 27∠90°

So, the ratio is ...

  z1/z2 = (6∠120°)/(27∠90°) = (6/27)∠(120°-90°)

  z1/z2 = (2/9)∠30°

8 0
3 years ago
What is the perimeter of the triangle?
Crazy boy [7]

Answer: 43

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A lawn darts team has choice of hitting a short field bonus throw or long zone bonus.
taurus [48]

Answer: i believe it is short field

7 0
4 years ago
Read 2 more answers
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