How do you find the difference between 6/8 - 1/7

1 answer:

8 0

Answer:to find the difference between 6/8 and 1/7, you need to make the denominators (the bottom numbers) the same. turn 6/8 into 42/56. then turn 1/7 into 8/56. you’ll then do 42/56-8/56. so it’ll be 42-8=36. so it will come out to 36/56, which is (when simplified) is 9/14. your answer will be 9/14.

Step-by-step explanation:

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A rectangular prism has volume 4,800 cubic yards, length 20 yards, and height 40 yards. Find its width, in yards.

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Answer: 6 yards.

Step-by-step explanation:

First, multiply the length and the height to get 800. You know now that 800 times the width will be your volume, 4800. To find the width, divide the volume by 800, which is the length times the height. Check your work by doing 40 times 20 times 6. You get 4800, which is your volume, which means your correct!

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A grocer takes a delivery of beverages from your truck at $6 per case. You unloaded 53 cases for the grocer today. How much does

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Step-by-step explanation:

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Is matrix multiplication comutative?

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Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

$A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]$