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Alexxandr [17]
3 years ago
8

What is the solution to the system of equations ?

Mathematics
1 answer:
miskamm [114]3 years ago
8 0
The answer to the question

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Show that: (3x-1)(x+5)(4x-3) = 12x^3 + 47x^2 - 62x +15 for all values of x. (3x-1)(x+5)(4x-3) = (?????)(4x-3) Expand into 6 term
lara31 [8.8K]
<span>(3x - 1)( x + 5)(4x - 3) = 12x^3 + 47x^2 - 62x +15 </span>
<span>(3x^2 – x + 15x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>(3x^2 + 14x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 9x^2 + 56x^2 – 42x – 20x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 47x^2 - 62x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>

<span> </span>

8 0
3 years ago
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Solve by writing an equation.
Karo-lina-s [1.5K]

Answer:

$115 - $48 = $67    Alberto has $67

5 0
3 years ago
Write the set of points from −2 to 6 but excluding 3 and 6 as a union of intervals:
KengaRu [80]

Answer:

[-2,6] - {3} - {6}  =   [-2,3)  ∪   (3,6)

Step-by-step explanation:

Union Of Intervals

Let us assume two interval A =  (a,b) and  C = (c,d).

Their union is written as :   A ∪ C = (a,b) ∪ (c,d)

Now, if interval is written in form [a,b] ⇒  a and b are INCLUDED in interval

Also, if interval is written in form (a,b) ⇒  a and b are NOT INCLUDED in interval

Here, the given interval is [-2,6]

excluding 3 and 6 from this will give:

[-2,3)  ∪   (3,6)

The first set is [-2.3)   where  -2 is INCLUDED but 3 is NOT INCLUDED.

The second set is (3,6)   where 3 and 6 both are  NOT INCLUDED.

Hence,   [-2,6] - {3} - {6}  =   [-2,3)  ∪   (3,6)

6 0
3 years ago
Find the distance between the points (2,4) and (5,0). (PLEASE HELP!)
Inessa05 [86]

Answer:

5

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (2, 4) and (x₂, y₂ ) = (5, 0)

d = \sqrt{(5-2)^2+(0-4)^2}

  = \sqrt{3^2+(-4)^2}

  = \sqrt{9+16} = \sqrt{25} = 5

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3 years ago
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What is 22.2% written as a fraction in simplest form
Mnenie [13.5K]
Proper fraction:
22 1⁄5

Improper fraction:
111⁄5
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3 years ago
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