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Pani-rosa [81]
2 years ago
5

An online flower service sells boxes of roses. Each box contains one dozen roses of only one color. The choices are red, white,

or pink. Based on the last 1000 orders, about how many boxes out of the next 100 orders will be for white or pink roses?
Mathematics
1 answer:
Akimi4 [234]2 years ago
6 0

Answer:

The answer is 21

Hope it helps

Please mark me as the brainliest

Thank you

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The area of a square battlefield was 22,500 square miles. How long will it take a group of soldiers to cross the field diagonall
VARVARA [1.3K]
\sqrt{22500} = s
\\\ diagonal = s \sqrt{2}
\\\ s = 150, \ diagonal = 150\sqrt{2}
\\\ diagonal \approx 212.132
\\\ 212.132/3.2 \approx 66.291 \ hrs
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Dana walks 3/5 mile in 1/4 hour. What is dana's walking rate in miles per hour?
Flura [38]
Here, our equation is 3/5 (0.6) mile per 1/4 (0.25) hour.  0.25 times 4 = 1, so we have to multiply 1/4 (0.25) 4 times to get 1 mile. To get a proportional answer, we must also multiply 3/5 (0.6) by 4. This comes out to 2.4. So her walking rate is 2.4 miles per hour.


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3 years ago
What 49/9 as a mixed number
enot [183]

Answer:

5 4/9

Step-by-step explanation:

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3 years ago
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fomenos
The last one is the answer
8 0
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Read 2 more answers
Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8
Gekata [30.6K]
First, let (x,y) be a point in our parabola. Since we know that the focus of our parabola is  the point (0,8), we are going to use the distance formula to find the distance between the two points:
\sqrt{(x-0)^{2}+(y-8)^{2}}

Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, y=c, is: |y-c|. Since our directrix is y=-8, the distance to our point will be:
|y-(-8)|
|y+8|

Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
\sqrt{(x-0)^{2}+(y-8)^{2}}=|y+8|
(\sqrt{(x-0)^{2}+(y-8)^{2}})^{2}=|y+8|^{2}
(x-0)^{2}+(y-8)^{2}=y+8

Finally, we can expand and solve for y:
x^2+y^2-16y+64=y^2+16y+64
x^{2}-16y=16y
32y=x^{2}
y= \frac{1}{32} x^2

We can conclude that t<span>he standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8 is </span>y= \frac{1}{32} x^{2}

3 0
2 years ago
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