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aliina [53]
3 years ago
15

The area of a rectangular of length L width W is given by the formula A =LW. Ann's backyard is rectangular with a length of 27.6

yards and a width of 10.9 yards. Find the area of ann's yard
Mathematics
1 answer:
marta [7]3 years ago
3 0

300.84m^2

First, set up the equation

A=27.6•10.9

Next, multiply(use a calculator)

And you get the answer.

^2 means squared.

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Nataly_w [17]
<span><span>Two Solutions
1. x =(10-√140)/4=(5-√<span> 35 </span>)/2= -0.458</span><span> 

2. x =(10+√140)/4=(5+√<span> 35 </span>)/2= 5.458</span></span>
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Need Help plz it has to be done now
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Step-by-step explanation:

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Wats the 60% off a prize that is $20.00
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3 years ago
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
Find the quotient of 394/6
uysha [10]

Answer:

65

Step-by-step explanation:

394/6

When 394 divided by 6 then

we get 65 quotient and 4 remainder

4 0
2 years ago
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