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4 years ago

How many moles are equal to 2.41x10 24 formula units of sodium chloride?

1 answer:

3 0

There are 6.022 x 10^23 formula units per mole

2.41 x 10^24 / 6.022 x 10^23 = 4.00 moles of Sodium Chloride

Hope I helped!

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Compound X has a molar mass of 283.89 mol^-1 and the following composition:

olchik [2.2K]

Explanation:

the above process is done in very detail .

hope this is helpful.

7 0

3 years ago

BALANCE THIS EQUATION: C4H10 + O2 = C02 + H20

Lostsunrise [7]

Answer:

${ \rm{C _{4} H_{10}+ \frac{13}{2} O _{2} = 4C0 _{2} + 5H _{2}0}} \\$

5 0

3 years ago

What is the percent by mass of oxygen in al2o3 ?

Snezhnost [94]

mr oxygen= 16. 16 x 3= 48
mr Al2O3= 27 + 27 + 48= 102

(48/102) X 100%= 47.05% oxygen

4 0

4 years ago

A compound possessing a carboxylic acid produces a yellow solution when dissolved in diethyl ether. This yellow solution is tran

Serga [27]

Answer:

A. The top layer will be diethyl ether, and the top layer will be yellow.

Explanation:

The purpose of the addition of the saturated aqueous solution of polar solvents like sodium chloride in the liquid-liquid extraction techniques is to remove as well as separate any kind of water which may be dissolved in the ether. Water and sodium chloride are both polar and thus, they forms the bottom layer and only ether forms the top layer. The compound being organic and is colored is in the top layer with the ether.

Hence, answer - A. The top layer will be diethyl ether, and the top layer will be yellow.

6 0

3 years ago

This means that the steel bar lost 14900 J of thermal energy. What is the change in temperature of the steel bar? Recall that th

stiv31 [10]

Answer:

ΔT=-747,13°C

Explanation:

Sensible heat is the amount of thermal energy that is required to change the temperature of an object, the equation for calculating the heat change is given by:

Q=msΔT

where:

Q, heat that has been absorbed or realeased by the substance [J]
m, mass of the substance [g]
s, specific heat capacity [J/g°C] (
ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=msΔT

ΔT=Q/ms

Δ $T=\frac{-14900 J}{40,7g*0,49\frac{J}{gC} }=-747,13$ °C

(Note that Q=-14900 J because there is a LOST of thermal energy)

Thus, the change in temperature of the steel bar is -747,13°C, meaning that the temperature of the bar decreases.

5 0

4 years ago

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