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JulsSmile [24]
2 years ago
7

What are some differences and similarities between male and female reproductive systems { Venn diagram }

Biology
1 answer:
Lady bird [3.3K]2 years ago
7 0
Male- private parts are different, Males have sperm that contributes to the reproduction process, males give 23 chromosomes like female's

Female- private parts are different, female's contributes eggs to the reproduction process, female's give 23 chromosomes like male
You might be interested in
A dermatome represents the motor innervation of muscles in what area.
Anon25 [30]

Answer:

A dermatome represents the unilateral area of skin on the body that is innervated by fibers from the sensory portion of a single spinal nerve coming from the spinal cord. Each spinal nerve contains spinal roots (anterior and posterior) that come together to form the spinal nerve.

Explanation:

3 0
3 years ago
Which of the following shows all of the tripeptides that can be formed from one molecule each of lysine (Lys), threonine (Thr),
Ierofanga [76]

Answer:

LysThrHis, LysHisThr, HisLysThr, HisThrLys, ThrLysHis, ThrHisLys

Explanation:

You easily combine the options for the tripeptide if you made a chart

Also you can calculate the posibilities with the factorial function in the calculatio (x!): 3*2*1 (you can multiplicate the number of amoniacids by the followed numbers until 1) = 6

7 0
3 years ago
Read 2 more answers
If a set of data is highly precise, what does this indicate about the accuracy of the data? It indicates that the data must have
lubasha [3.4K]
If a set of data is highly precise, it generally "indicates that the data must have a high level of accuracy" although there can be other crucial factors affecting the data as well.
6 0
2 years ago
Read 2 more answers
An owl has good night vision because its eyes can detect a light intensity as small as 5.0 × 10-13 W/m2. What is the minimum num
Lady bird [3.3K]

Answer:

Thus, the minimum number of photons per second is 77.34

Explanation:

Light intensity, I_{min} =  5\times 10^{-13} W/m^{2}

Pupil has a diameter, d = 8.5 mm

                                      = 8.5 x 10^{-3} m

Radius of the eye, r = 4.25 x 10^{-3} m

∴ Area of the eye, A = \pi .r^{2}

                                 = 3.14\times \left ( 4.25\times 10^{-3} \right )^{2}

                                = 5.6\times 10^{-5} m^{2}

Let P_{min} be the minimum number of photons.

Therefore, P_{min} = I_{min} x A

                                              = 5\times 10^{-13} x 5.6\times 10^{-5}

                                             = 2.8\times 10^{-17} W

Thus the minimum number of photons is given by

N_{min}=P_{min}/E

where E = hc/\lambda

             = \left (6.63\times 10^{-34}\times 3\times 10^{8}  \right )/548\times 10^{-9}

            = 3.62\times 10^{-19} J

Therefore, N_{min} = \frac{2.8\times 10^{-17}}{3.62\times 10^{-19}}

                                              = 77.34 photons per second

Thus, the minimum number of photons per second is 77.34

4 0
3 years ago
Assume that the left ventricle of a child's heart has an EDV=90mL, and ESV=60mL, and a cardiac output of 2,400 mL/min. His SV is
Sliva [168]

Answer:

SV = 30 ml/ beat.

HR = 80.

Explanation:

The formula to calculate SV is as follows:

SV = EDV- ESV.

Here EDV = 90ml (end diastolic volume), ESV = 60ml (end systolic volume) ans SV is stroke volume.

SV = 90-60

SV = 30ml/beat.

The formula to calculate HR is as follows:

HR = CO/SV

Here, HR is heart rate, CO is cardiac output = 2,400 ml/min and SV is stroke volume = 30ml/beat

HR = 2,400/30

HR = 80.

Thus, the SV is 30ml/best and HR is 80.

4 0
2 years ago
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