Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
Demeter International
Explanation:
Demeter International is the primary certification agency for farms and gardens using the methods. In the United States, bio-dynamic farming dates from 1926.-
Condominance is the answer hope it helps
Answer:
The correct answer is A. Tobacco mosaic virus
Explanation:
Virus can have DNA and RNA as its genetic material. Tobacco mosaic virus has RNA as its genetic material. Protein is not a genetic material because it is a product coded by genetic material.
So a hybrid can be made only when the genetic material of two different organisms is mixed not two different biomolecules. Therefore when RNA from the tobacco mosaic virus is mixed with the protein from a DNA virus the result would be a tobacco mosaic virus only.
