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xenn [34]
3 years ago
5

A bag of marbles has 5 red, 2 blue, and 3 green marbles. A marble is randomly selected. What is the probability AS A DECIMAL tha

t a blue marble is pulled?​
Mathematics
1 answer:
loris [4]3 years ago
8 0

Answer:

0.25 Hope this helps :)

Step-by-step explanation:

You add the 5 red and 3 green

8 Mables besides blue

so that's 2/8

simplified 1/4

1/4=0.25

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Zack bought a coat for $69.78 .He paid with a $100 bill and received $26.73 in change.How much was the sales tax? plz help ill g
yKpoI14uk [10]
100-69.78-26.73=3.49

The sales tax was $3.49.
8 0
3 years ago
Read 2 more answers
170 is 1/10 of 17 true or false 170 is 1/10 of 17 true or false
Zarrin [17]
Let's see if that's really true! :)


170=x(17)
170=17x
17x=170
17x / 17=170 /  17
x=10

So the answer to your question is false.

170 is actually 10/1 OR 10 of 17.

6 0
3 years ago
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
Leona [35]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: flexural strength of concrete beams.

Data:

7.3 6.8 8.6 9.7 11.6 9.7 6.8 7.7 11.8 7.4 8.1 8.7 6.3 7.9 7.0 7.9 7.8 6.5 6.3 7.0 7.5 7.7 7.2 11.3 9.0 10.7 5.1

a.

The point estimate of the mean value is the sample mean. You calculate it using the following formula:

X[bar]= ∑X/n= 219.40/27= 8.1259≅ 8.13

b)x

b.

The point estimate that divides the sample in 50%-50% is the measure of central tendency called Median(Me).

To reach the median you have to calculate it's position (PosMe)

For uneven samples PosMe= (n+1)/2= (27+1)/2= 14 ⇒ This means that the Median is the 14th observation of the data set.

So next is to order the data from lower to heighest and identify the value in the 14th position:

5,1 ; 6,3; 6,3; 6,5 ; 6,8; 6,8; 7; 7; 7,2; 7,3; 7,4 ; 7,5 ; 7,7 ; 7,7 ; 7,8 ; 7,9 ; 7,9 ; 8,1 ; 8,6 ; 8,7 ; 9 ; 9,7 ; 9,7 ; 10,7 ; 11,3 ; 11,6 ; 11,8

Me= 7.7

d) x tilde

c.

The point estimate of the population standard deviation is the sample standard deviation. The standard deviation is the square root of the variance, so the first step is to calculate the sample variance:

S^2= \frac{1}{n-1}*[sumX^2-\frac{(sumX)^2}{n} ]

∑X²= 1858.92

S^2= \frac{1}{26}*[1858.92-\frac{219.40^2}{27} ] = 2.926

S= √2.926= 1.71

The standard deviation is a measurement of variability, it shows how to disperse the data is concerning the sample mean.

d. This estimate describes the spread of the data.

I hope it helps!

7 0
3 years ago
When Emily arrives from school she spent a minute eating a snack then she spent 15 playing with her dog and 32 doing her chores
Neporo4naja [7]

The question is incomplete:

When Emily arrived home from school she spent a minutes eating a snack. Then, she spent 15 minutes playing with her dog and 32 doing her chores . Finally, Emily spent 45 minutes finishing her homework. How long had Emily been home when she finished?

Answer:

Emily had been home for 1 hour and 33 minutes.

Step-by-step explanation:

In order to find the answer, first you have to add up the time she spent in each activity to find the amount of minutes she had been at home when she finished:

1+15+32+45=93

Now, you can express the 93 minutes in hours considering that one hour has 60 minutes. According to this, Emily had been home for 1 hour and 33 minutes (93-60=33).

8 0
2 years ago
Find upper and lower limit of a weight of a cotton reel which is 1.56g nearst to mg
Papessa [141]

Answer: the lower limit is 1.555g and the upper limit is 1.564g

Step-by-step explanation:

a mg is:

1mg = 0.001g

Then we need to look at the third digit after the decimal point.

Then the weight 1.56g is rounded around this.

Remember that if the third digit after the decimal point is 5 or bigger, then we round up.

if the third digit is smaller than 5, then we round down.

Now, the maximum possible value of this weight is when the third digit is equal to 4 (4 mg) where because it is smaller than 5, we round it down to 1.56g

Then the maximum is 1.564g

And the minimum value is when we have:

w = 1.555g

Because the third digit is a 5, we round it up to 1.56g.

So the lower limit is 1.555g and the upper limit is 1.564g

4 0
3 years ago
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