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Andrews [41]
3 years ago
14

Select the vertical asymptote(s) of the function

7B%28x-2%29%28x%2B6%29%7D" id="TexFormula1" title="f(x)=\frac{(x+6)(x-1)}{(x-2)(x+6)}" alt="f(x)=\frac{(x+6)(x-1)}{(x-2)(x+6)}" align="absmiddle" class="latex-formula">
A. x=2
B. x=-6
C. x=2, x=-6
D. x=-2
Mathematics
2 answers:
Bess [88]3 years ago
4 0

Answer:

As the described function, we want to find vertical asymtotes, we find the value of x so that the denominator is equal to 0.

Here, (x - 2)(x + 6) = 0

=> x = 2, x =-6

=> Option C is correct.

Hope this helps!

:)

Julli [10]3 years ago
4 0

Answer:

A. x = 2

Step-by-step explanation:

(x+6)(x-1) ÷ (x-2)(x+6)

Since x+6 is common to both, numerator and denominator, it will get cancelled out

And there will be a hole at x = -6

The simplified form would be

(x-1)/(x-2)

There will be a vertical asymptote at x = 2, because the denominator becomes zero at x = 2

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