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3 years ago

What is another name for line m?

Mathematics

1 answer:

Ganezh [65]3 years ago

5 0

I’m pretty sure it’s the slope

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Solve each proportion 8 into v=56 into 105

TiliK225 [7]

So what does 8 go into 56 and 56 must go into 105 and the answer that you got in 8 goes into 56 should be the same answer as you got 56 to go in 105

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3 years ago

Is a^-b = -a^b? PLEASE ANSWER!!

jeyben [28]

No! 2^-3 is not equal to -3^2

8 0

4 years ago

What is the slope of the line represented by the graph?

Anettt [7]

Answer: B.

Step-by-step explanation:

There's a change of 1 in y for every 2 changes in x.

8 0

3 years ago

Need help with this math question

anastassius [24]

Answer:

The vertex is: $(6, 8)$

Step-by-step explanation:

First solve the equation for the variable y

$x^2-4y-12x+68=0$

Add 4y on both sides of the equation

$4y=x^2-4y+4y-12x+68$

$4y=x^2-12x+68$

Notice that now the equation has the general form of a parabola

$ax^2 +bx +c$

In this case

$a=1\\b=-12\\c=68$

Add $(\frac{b}{2}) ^ 2$ and subtract $(\frac{b}{2}) ^ 2$ on the right side of the equation

$(\frac{b}{2}) ^ 2=(\frac{-12}{2}) ^ 2\\\\(\frac{b}{2}) ^ 2=(-6) ^ 2\\\\(\frac{b}{2}) ^ 2=36$

$4y=(x^2-12x+36)-36+68$

Factor the expression that is inside the parentheses

$4y=(x-6)^2+32$

Divide both sides of the equality between 4

$\frac{4}{4}y=\frac{1}{4}(x-6)^2+\frac{32}{4}$

$y=\frac{1}{4}(x-6)^2+8$

For an equation of the form

$y=a(x-h)^2 +k$

the vertex is: (h, k)

In this case

$h=6\\k =8$

the vertex is: $(6, 8)$

5 0

3 years ago

The line y−6=2(x+4) passes through which point?

astra-53 [7]

Answer:

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3 years ago