Which percent is equivalent to the fraction 7/50 ?

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

Answer:

7/50 = 14%

Step-by-step explanation:

Step 1: Top dawg in the house (the numerator becomes the dividend)

So instead of putting 50÷7 into the calculator, you would do 7÷50, which equals 0.14.

Step 2: Turn your decimal to a fraction.

Your decimal is 0.14. The last number of this decimal is in the HUNDREDTHS place. Therefore, you should MULTIPLY BY 100, or MOVE YOUR decimal two places to the RIGHT, which is 14.

All in all, 7/50 = 14%

taurus [48]3 years ago

5 0

14% because 7/50 divided by 100 equals 14.

You might be interested in

What is the side length of the square??

Elena-2011 [213]

Answer:

Step-by-step explanation:

1. On the x-axis, count how many boxes are filled from left to right, starting from 0.

2. On the y-axis, count how many boxes filled from bottom to up, starting from 0.

4 0

3 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$