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Kamila [148]
4 years ago
12

PLEASE HELP!! what is the domain of the function below???

Mathematics
2 answers:
Anvisha [2.4K]4 years ago
7 0

f(x) = 57 (19)^(x-4)

The domain is the input or x values

what are the allowed x values

we can put in any values of x we want and the function still works

Domain: all real values  

The range is the output or the y values

It will always be greater than 0

Range: y> 0  or all positive real numbers

myrzilka [38]4 years ago
5 0

The domain is any real number

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8x2 - 6x + 3 – 2x – 10x?
Marina CMI [18]

Answer:

8x^{2} + 3 + -6x

Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8x^{2} + 3 + (6x - 2x - 10x)

=> 8x^{2} + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

4 0
3 years ago
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Select all the equivalent to a^2/a^9 assume a doesnt equal 0
Alenkinab [10]
a ^ 2 / a ^ 9
 For this case what you should do is use the power properties to write the expression in different ways.
 Three different ways to write the expression are:
 Way 1:
 a ^ 2 / a ^ 9 = a ^ (2-9) = a ^ (- 7) = 1 / a ^ 7
 1 / a ^ 7
 Way 2:
 a ^ 2 / a ^ 9 = a ^ (2-9) = a ^ (- 7)
 a ^ (- 7)
 Way 3:
 a ^ 2 / a ^ 9 = a ^ 2 * a ^ (- 9)
 a ^ 2 * a ^ (- 9)
 Answer:
 
all the equivalent to a ^ 2 / a ^ 9 are:
 
1 / a ^ 7
 
a ^ (- 7)
 
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If x+y is rational,must x and y each br rational?
aniked [119]

Answer:

No.

Step-by-step explanation:

x and y could be irrational and x+y be rational.

Example:

Let x=\sqrt{2} and y=-\sqrt{2}.

And x+y=\sqrt{2}+-\sqrt{2}=0 and 0 is rational.

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yuradex [85]
If this is not correct sorry I think it is tho

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3 years ago
Joe earns $13.40 an hour and it's paid every two weeks. Last week he worked seven hours longer than a week before. His pay for t
lyudmila [28]

Answer:

51

Step-by-step explanation:

divied the two numbers

6 0
3 years ago
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