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3 years ago

10

What is 1+1 cuz honestly idk

2 answers:

dedylja [7]3 years ago

6 0

Answer:

21 lol

Step-by-step explanation:

2

Readme [11.4K]3 years ago

5 0

2

✌

one finger+ one finger= one + one= 1 +1=

2
two

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Help me please...!!!!!!

goblinko [34]

B would be the answer for sure

4 0

4 years ago

Read 2 more answers

Sin (x/2)= √2- sin (x/2) solve for the exact solutions in the interval (0, 2π)

serg [7]

$sin\left( \frac{x}{2} \right)=\sqrt{2}-sin\left( \frac{x}{2} \right)\implies sin\left( \frac{x}{2} \right)+sin\left( \frac{x}{2} \right)=\sqrt{2}\implies 2sin\left( \frac{x}{2} \right)=\sqrt{2} \\\\\\ sin\left( \cfrac{x}{2} \right)=\cfrac{\sqrt{2}}{2}\implies sin^{-1}\left[ sin\left( \cfrac{x}{2} \right) \right]=sin^{-1}\left( \cfrac{\sqrt{2}}{2} \right) \implies \cfrac{x}{2}= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4} \end{cases} \\\\[-0.35em] ~\dotfill$

$\cfrac{x}{2}=\cfrac{\pi }{4}\implies \boxed{x=\cfrac{\pi }{2}}~\hfill \cfrac{x}{2}=\cfrac{3\pi }{4}\implies \boxed{x=\cfrac{3\pi }{2}}$

5 0

3 years ago

I need help please with this 1 problem

Lyrx [107]

Answer:

See below, please

Step-by-step explanation:

We know

$f(x) = {x}^{2} + 3x - 7$

$g(x) = 3x + 5$

$h(x) = 2 {x}^{2} - 4$

Hence

$f(g(x))$

$= {(3x + 5)}^{2} + 3 \times (3x + 5) - 7$

$= (9 {x}^{2} + 30x + 25) + (9x + 15) - 7$

$= 9 {x}^{2} + 39x + 33$

$h(g(x))$

$= 2 \times {(3x + 5)}^{2} - 4$

$2 \times (9 {x}^{2} + 30x + 25) - 4$

$= 18 {x}^{2} + 60x + 50 - 4$

$= 18 {x}^{2} + 60x + 46$

$(h - f)(x)$

$= h(x) - f(x)$

$= (2 {x}^{2} - 4) - ( {x}^{2} + 3x - 7)$

$= {x}^{2} - 3x + 3$

$(f + g)(x)$

$= f(x) + g(x)$

$= ( {x}^{2} + 3x - 7) + (3x + 5)$

$= {x}^{2} + 6x - 2$

5 0

3 years ago

Please solve 9 if it’s upside down please rotate it

topjm [15]

Answer:

≈ 1/2 teaspoon

4 2/5 * .11 = .484 teaspoon

Hope this helps :)

<em>ilovejiminssi♡</em>

7 0

3 years ago

[I need the answer asap because my teacher wants this done today!] Which y coordinate can be found on the house?

Lynna [10]

Answer:

Your answer should be 5.

Hope this helps. :-)

3 0

4 years ago