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4 years ago

Pls help Simplify the product. 4(–11)

Mathematics

2 answers:

sattari [20]4 years ago

8 0

-44 lol yup yup yesss :))

Shalnov [3]4 years ago

3 0

Answer:

-44

Step-by-step explanation:

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Twenty minutes to six in the evening on a 24 hour clock

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3 years ago

Given the equation y=23x,whats the value of x if y=100

Damm [24]

Answer: 4.3478 or 100/23

Step-by-step explanation:

Set the y values equal to each other since they are the same unknown (x). You end up with 100=23x, solve for x. Move the 23 over to the other side by using division. x=100/23. If you need it in decimal form, 100÷23=4.347826087

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3 years ago

Read 2 more answers

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

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3 years ago

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Allisa [31]

Answer:

Yes, by SAS

Step-by-step explanation:

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3 years ago

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Veronika [31]

Answer:

Quadrant III

Step-by-step explanation:

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3 years ago