Which of the binomials below is a factor of this trinomial ? X^2 + x + 12
1 answer:
That trinomial can't be factored. You would have to complete the square to factor it and even then your answer would be an imaginary number.
x² + x + 12 = 0
x² + x = - 12
x² + x + 1/4 = - 12 + 1/4
x² + x + 1/4 = - 11 3/4
x² + x + 1/4 = - 47/4
(x + 1/2)² = - 47/4
x + 1/2 = +/- √(- 47/4)
x + 1/2 = +/-
x = 1/2 +/-
If the constant was a negative, it would be factor-able (is that a word?).
x² + x + 12 = 0
x² + x = - 12
x² + x + 1/4 = - 12 + 1/4
x² + x + 1/4 = - 11 3/4
x² + x + 1/4 = - 47/4
(x + 1/2)² = - 47/4
x + 1/2 = +/- √(- 47/4)
x + 1/2 = +/-
x = 1/2 +/-
If the constant was a negative, it would be factor-able (is that a word?).
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PQRS is a circle, PQT and SRT are straight lines.
To find:
The value of x.
Solution:
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We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.
Now, SRT is a straight line.
(Linear pair)
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Using exterior angle theorem in triangle QRT, we get
Therefore, the value of x is 103 degrees.