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Feliz [49]
3 years ago
6

WILL GIVE THE PERSON WHO ANSWERS BRAINLIEST AWARD!!!! Which is a true statement about the dot plot? Number of Rolls of a Six-Sid

ed Number Cube to Get an Even Number The data is skewed left. There is a cluster at 1, 2, and 3. It never took more than 4 rolls to get an even number. Most often it took 3 rolls to get an even number.
Mathematics
2 answers:
rusak2 [61]3 years ago
6 0

Answer:

<h2>It never took more than 4 rolls to get an even number</h2>

hope this helps

DerKrebs [107]3 years ago
3 0

The question was a bit confusing, and I have been searching for similar question. I found a picture similar to description about the dot plot as below:

1: 4 dots

2: 8 dots

3: 4 dots

4: 2 dots

5: 1 dot

Answer:

It never took more than 4 rolls to get an even number

Step-by-step explanation:

Total dots by even number: 8 + 2

Pr(even) = 10/19 = 1/1.9

In other word, for every 1.9 rolls (or 2 rolls), 1 will be even.

The data is skewed to the right since most of the rolls occupied by number 1,2 and 3.

And there is no prove that the event is being clustered, hence less likely to be cluster sampling

It doesn't take 3 rolls to get even number. 2 rolls needed to get even number.

The most correct answer should be 'it never take more than 4 rolls to get even number' since it only took 2 rolls to get an even number.

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On the number line below. P number what is the value of the opposite of that number.​
Katena32 [7]

Answer: -1 2/4 is the opposite of 1 2/4

Step-by-step explanation: On the number line the P represents 1 2/4, so the opposite of that is -1 2/4.

Also as I stated before I recently did this test.

FLVS right, segment practice test?

Hope this helped fellow FLVS student!!

4 0
3 years ago
3. Find cos(A). Show your work and reduce the ratio if necessary.
anygoal [31]

Answer:

cosA = \frac{3}{5}

Step-by-step explanation:

cosA = \frac{adjacent}{hypotenuse} = \frac{AB}{AC} = \frac{30}{50} = \frac{3}{5}

5 0
3 years ago
Gabriela has dinner at a cafe and the cost of her meal is $45.00. Because of the service,she wants to leave a 15%tip. What is he
Kitty [74]
45+(45*.15)=
45+6.75=51.75
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5 0
3 years ago
1.) what is the length of the diagonal for the given rectangular prism to the nearest whole unit?
N76 [4]
The answer is D.10 at least
3 0
3 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
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