All categories

3 years ago

What are recriprocals

Mathematics

2 answers:

stepladder [879]3 years ago

8 0

Two numbers are called reciprocals if their product is equal to 1.
Hope this helps~

irga5000 [103]3 years ago

3 0

Reciprocal is another word for flip...... So like, 3/4, when you recriprocal it, it would be 4/3! Hope this helps!

You might be interested in

Simplify: 3-2 what is this awnser

sweet [91]

Answer:

It is ................................................................. 1

Step-by-step explanation:

7 0

2 years ago

Which phrase describes an unknown or changeable quantity/

Helen [10]

Answer:
C. 2 times the number of pages in the book

Explanation:
The number of pages of the book may vary or can change depending on the book

6 0

3 years ago

If 4 divides a^2-3b^2, then at least one of the integers a and b is even.

OleMash [197]

Answer:

Step-by-step explanation:

Suppose, on the contrary, a and b are both odd integers, that is:

$a=2n+1\\\\b=2m+1\\\\$

m and n being some integers numbers.

This way you have to:

$a^{2}-3b^{2}=(2n+1)^2-3(2m+1)^2=(4n^2+4n+1)-3(4m^2+4m+1)\\\\a^{2}-3b^{2}=4(n^2-3m^2+n-3m)-2=4(n(n+1)-3m(m+1))-2$

The last expression cannot be divisible by 4 since 2 is not divisible by 4. The previous conclusion leads to a contradiction, which was generated from the assumption that a and b were both odd integers. In conclusion, at least one of the two a and b should be an even integer

3 0

2 years ago

Select all of the equations that are equivalent to

Citrus2011 [14]

Answer:

The options 2√20 and 4*5^(1/2) and 3*5^(1/2) + 5^(1/2) are the only expressions that are equivalent to 4√5

Step-by-step explanation:

We will factorise and simplify each term to get 4√5 in the end:

a) 2√20

2√5*4

2√5√4

2*2√5 Because √4 = 2

4√5

b)6^1/2 +5^1/2

√6 + √5

√2√3 + √5

c) 3*5^(1/2) + 5^(1/2)

3*√5 + √5

√5 (3*1 + 1)

√5 (3 + 1)

√5 (4)

4√5

d) 4*5^(1/2)

4√5 Because any integer with power 1/2 = √

e) 2√10

2√5*2

2√5√2

f) 3*5^(1/2)

3√5

8 0

2 years ago

Rationalize (4+√5)/(√15-√8)

dalvyx [7]

Answer:

$\frac{4\sqrt{15} +8\sqrt{2}+5\sqrt{3} +2\sqrt{10} }{7}$

Step-by-step explanation:

$\frac{4+\sqrt{ 5}}{\sqrt{15}-\sqrt{8} }$

To rationalize the above fraction multiple both numerator and denominator by the conjugate of its denominator.

$\frac{4+\sqrt{ 5}}{\sqrt{15}-\sqrt{8} }*\frac{\sqrt{15}+\sqrt{8} }{\sqrt{15} +\sqrt{8} }$

We can simplify √8 like this :

√8 = √4 × √2

√8 = 2√2

Let us rationalize the above fraction now.

$\frac{4+\sqrt{ 5}}{\sqrt{15}-\sqrt{8} }*\frac{\sqrt{15}+\sqrt{8} }{\sqrt{15} +\sqrt{8} }\\ \\\\\frac{(4+\sqrt{ 5})}{(\sqrt{15}-\sqrt{8}) }*\frac{(\sqrt{15}+2\sqrt{2} ) }{(\sqrt{15} +\sqrt{8})}$

Solve the brackets and roots.

$\frac{4(\sqrt{15}+2\sqrt{2})+\sqrt{5} (\sqrt{15} +2\sqrt{2}) }{\sqrt{ 15} * \sqrt{15} - \sqrt{8} * \sqrt{8} } }\\\\\\\frac{4\sqrt{15} +8\sqrt{2}+\sqrt{75}+2\sqrt{10} }{15-8}$

Simplify the roots.

√75 = √25 × √3

√75 = 5√3

$\frac{4\sqrt{15} +8\sqrt{2}+\sqrt{75}+2\sqrt{10} }{15-8}\\\\\\\frac{4\sqrt{15} +8\sqrt{2}+5\sqrt{3} +2\sqrt{10} }{7}$

8 0

1 year ago

Read 2 more answers