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mylen [45]
3 years ago
11

please help me i don't know how to do this and i need help i been struggling for 2 hours please help me i really need help help

is really appreciated please ​

Mathematics
2 answers:
Rasek [7]3 years ago
4 0

Vertex: (4,0)

Axis of symmetry: x = 4

Klio2033 [76]3 years ago
4 0

Answer:

Vertex: (4, 0)

Axis of symmetry: x = 4

Step-by-step explanation:

This quadratic is in vertex form.  Vertex form is

y = a(x - h)² + k     where the point (h, k) is the vertex.  

For this equation we have

y = -(1/8)(x - 4)² + 0,   so our vertex is at the point (4, 0)  

*It's positive 4 because the equation is (x - h), so we're subtracting positive 4

The axis of symmetry is the equation of the vertical line that goes through the x coordinate of the vertex (quadratics are symmetric from the vertex)

So the axis of symmetry is x = 4

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311 students went on a field trip. Six buses were
kow [346]

Answer:

50.6

Step-by-step explanation:

it says 7 students traveled by car so you need to take 7 from 311, then divide your answer (304) by 6, which is 50.6

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3 years ago
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:. 7p + 4p - 10 = 6p
sergiy2304 [10]

Answer:

\boxed {p = 2}

Step-by-step explanation:

Solve the value of p:

7p + 4p - 10 = 6p

-Combine like terms:

7p + 4p - 10 = 6p

11p - 10 = 6p

-Take 6p and subtract it from 7p:

11p - 10 - 6p = 6p - 6p

5p - 10 = 0

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5p - 10 + 10 = 0 + 10

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\boxed {p = 2}

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6 0
4 years ago
In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

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