No, the sum of the lengths of any two sides must be greater than the length of the third side
Answer:
<h2>0, 3, 8, 15</h2>
Step-by-step explanation:
Substitute n = 1, n = 2, n = 3 and n = 4 to the equation f(n) = n² - 1:
f(1) = 1² - 1 = 1 - 1 = 0
f(2) = 2² - 1 = 4 - 1 = 3
f(3) = 3² - 1 = 9 - 1 = 8
f(4) = 4² - 1 = 16 - 1 = 15
Rectangle:
A=l(w)
A=12(6)
A=72cm^2
Semicircle:
r=6/2
r=3
A=(3.14(r)^2(1/2)
A=3.14(3)^2(1/2)
A=3.14(9)(1/2)
A=14.13cm^2
A=14.1cm^2
Total area: 72cm^2 + 14.1cm^2 = 86.1cm^2
By definition, the volume of the cone is given by:
V = (1/3) (π) (r ^ 2) (h)
Substituting values we have:
V = (1/3) (π) ((4/2) ^ 2) (5)
V = (20/3) (π)
Then, the volume of the cylinder is:
Vc = 3 * V
Vc = 3 * (20/3) (π)
Vc = 20π
Answer:
the volume of the original cylinder jesse bought is:
Vc = 20π