Answer:
c) 0.0156
Step-by-step explanation:
The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...
a[n] = a[1]r^(n-1)
The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...
a[n] = 8(1/2)^(n-1)
The 10th term is then ...
a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512
a[10] = 0.015625 ≈ 0.0156
Answer:
63.7999... (repeating) fps
Step-by-step explanation:
Feet per second (fps) per one (1) mph is 1.4666... repeating
so 43.5 * 1.46666... = 63.7999.. repeating
hope this helps:)
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
#SPJ4
Answer:
quadrant 1.
Step-by-step explanation:
A:(9,3)
B:(7,5)
C:(5,2)
Hope this helped you.
