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3 years ago

Help me with all of them plzzz eleven Points

Mathematics

2 answers:

irina [24]3 years ago

5 0

122 with 58
35 with 145
62 with 118
105 with 75

Likurg_2 [28]3 years ago

5 0

1. Is 24/30 sorry can't help with the rest

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Oksana_A [137]

Answer:

1: Sides

2: like terms

Step-by-step explanation:

3 0

2 years ago

31*r+1.1*(35−31)*r = 410.64.

Rasek [7]

Answer:

11.6

Step-by-step explanation:

<u>Solving with steps as below:</u>

31*r+1.1*(35−31)*r = 410.64
31r + 1.1*4r = 410.64
31r + 4.4r = 410.64
35.4r = 410.64
r = 410.64/35.4
r = 11.6

<u>Answer is:</u> r =11.6

5 0

3 years ago

The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point

iren [92.7K]

Absolute value
at x=2, the absolute value thing is positive
do this one
$y=x \sqrt{5-x^2}$
the derivitive is
$\frac{dy}{dx}=\sqrt{5-x^2}- \frac{x^2}{ \sqrt{5-x^2} }$
so the slope at x=2 is
$\frac{dy}{dx}=\sqrt{5-2^2}- \frac{2^2}{ \sqrt{5-2^2} }$ =-3

a point is (2,2)
point slope form
y-y1=m(x-x1)
y-2=-3(x-2)
or
y=-3x+8
das is de equation

3 0

2 years ago

Suppose there are two lakes located on a stream. Clean water flows into the first lake, then the water from the first lake flows

never [62]

Answer:

a. For the first lake;

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m·t/200 - m·t²/80000

b. t ≈ 1.00505 hours

c. 200 hours

Step-by-step explanation:

The flow rate of water in and out of the lakes = 500 liters/hour

The volume of water in the first lake = 100 thousand liters

The volume of water in the second lake = 200 thousand liters

The mass of toxic substances that entered into the first lake = 500 kg

The concentration of toxic substance in the first lake = m₁/(100000)

Therefore, we have;

The quantity of fresh water supplied at t hours = 500 × t

The change

The change in the mass of the toxic substance with time is given as follows

dm/dt = (m - m/100000 × 500 × t)/100000

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m/100000 × 500 × t - (m/100000 × 500 × t)/200000 × 500 × t

Using an online tool, we have;

c = m·t/200 - m·t²/80000

b. When c < 0.001 kg per liter, we have m < 0.001 × 100000, which gives m < 100

Substituting gives;

0.001 = (100·t - 0.005·100·t²)/100000, solving with an online tool, gives;

t ≈ 1.00505 hours

c. For maximum concentration, we have;

c = m·t/200 - m·t²/80000

m/200000 = m·t/200 - m·t²/80000

1/200000 = t/200 - t²/80000

dc/dt = d(t/200 - t²/80000)/dt = 0

Solving with an online tool gives t = 200 hours

6 0

2 years ago

Write an equation for the nth term of the arithmetic sequence. -6,-9,-12,-15

poizon [28]

Answer:

$a_{n}$ = - 3n - 3

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 6 and d = a₂ - a₁ = - 9 - (- 6) = - 9 + 6 = - 3 , then

$a_{n}$ = - 6 - 3(n - 1) = - 6 - 3n + 3 = - 3n - 3

6 0

2 years ago