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skad [1K]
4 years ago
11

A line passes through the points

Mathematics
2 answers:
Likurg_2 [28]4 years ago
8 0

Hi there! :)

Step-by-step explanation:

SLOPE=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{5-4}{2-(-2)}=\frac{1}{4}

<u><em>Slope is 1/4.</em></u>

<u><em>Final answer is 1/4.</em></u>

Hope this helps!

Have a nice day! :)

:D

-Charlie

Thank you so much! :)

:D

VLD [36.1K]4 years ago
6 0

Hey there!

To find the slope, we can use the rise over run formula.

Rise is the change in y, and run is the change in x.

The change in y is 1, and the change in x is 4.

1 ÷ 4 = 1/4 or .25

<u>The slope of the line is 0.25 or 1/4.</u>

Hope this helps!

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Step-by-step explanation:

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A density curve for all the possible temperatures between 0 degrees F and 40 degrees F is a rectangle. What is the height of the
Eddi Din [679]

Answer:

Concept: Higher Level Mathematics

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3 0
3 years ago
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9( 2k + 3 ) + 2 = 11 ( k- y )
Mashcka [7]
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8 0
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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
4 years ago
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