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Tanzania [10]
3 years ago
8

What reproductive process do bacteria use by forming two identical cells from one parent cell?

Chemistry
2 answers:
Fed [463]3 years ago
4 0

Answer:

A: binary fission

Explanation:

nikdorinn [45]3 years ago
3 0
This is a kind of an asexual reproduction called binary fission. This involves division of the parent cell into two identical cells. This is common for prokaryotic reproduction like archaea and bacteria and it also happens in some single-celled eukaryotes such as protists and unicellular fungi.
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LICUICY NICULUM
Evgen [1.6K]

Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

? + 2NaBr → 2NaCl+Br

Mg+? → MgO+H2

missing component = ?

Solution:

Reaction 1

             ? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

Br (Bromine)

So only Chlorine is missing in the reactant side.

if we put chlorine in the reactant then this reaction will be complete

        Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

          Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

  • Cl₂

____________

Reaction 2

                Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

          Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

  • H₂O

3 0
3 years ago
Read 2 more answers
Determine the freezing point of a water solution of fructose (C6H12O6) made by dissolving 92.0 g of fructose in 202 g of water.
Naya [18.7K]

Answer:

THE FREEZING POINT OF A WATER SOLUTION OF FRUCTOSE MADE BY DISSOLVING 92 g OF FRUCTOSE IN 202g OF WATER IS -4.70 ◦C

Explanation:

To calculate the freezing point of a water solution of fructose,

1. calculate the molar mass of Fructose

( 12 * 6 + 1*12 + 16*6) =72 + 12 +96 = 180 g/mol

2. calculate the number of moles of fructose in the solution

number of moles = mass / molar mass

n = 92 g / 180 g/mol

n = 0.511 moles.

3. calculate the molarity of the solution

molarity = moles / mass of water in kg

molarity = 0.5111 / 202 g /1000 g

molarity = 0.5111 / 0.202

molarity = 2.529 M

4. calculate the change in the freezing point of pure solvent and solution ΔTf

ΔTf = Kf * molarity of the solute

Kf = 1.86 ◦C/m for water

ΔTf = 1.86 * 2.529

ΔTf = 4.70 C

5. the freezing point is therefore

0.00 ◦C - 4.70 ◦C = -4.70 ◦C

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!
kondaur [170]
Number of moles of HCl = \frac{mass (g)}{molar mass}
                = \frac{27.8 g}{36.45} = 0.763 mole
From balanced equation:
4 moles of HCl give 2 moles Cl2
0.763 mole HCl give ?? mole Cl2
by cross multiplication :
= 0.38 mole Cl2
mass of Cl2 = moles x molar mass = 0.38 x 70.9 = 27 g 
3 0
4 years ago
Read 2 more answers
A 74 kg zebra is traveling 15 m/s east. What is the zebra’s momentum
svetoff [14.1K]
Mass × velocity = momentum 

74 x 15 = momentum
7 0
4 years ago
How many electrons make up a charge of -50.0 μc ? Express your answer using three significant figures?
SVETLANKA909090 [29]

The charge on one mole of electrons = 96485 C =  1 Faraday

so if charge is 96485 C the moles of electrons are 1 = 6.023 X 10^23 electrons

if charge is 1 C the number of electrons = 6.023 X 10^23 / 96485

If charge is 50 micro C the number of electrons

              = 6.023 X 10^23 X 50 X 10^-6 / 96485

             = 3.12 X 10^14 electrons


5 0
3 years ago
Read 2 more answers
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