The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
Answer:
Explanation:
Step 1. Calculate the pOH
pOH =-log[OH⁻]
pOH =-log(1.0 × 10⁻⁹)
pOH = 9.00
Step 2. Calculate the pH
pH + pOH = 14.00
pH + 9.00 = 14.00
Answer:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
Explanation:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
H+
O2-
OH-
Ba2+
Ca2+
NO3-
P 5+, 3+, 3-
H2O
Answer:
the 2 means there are 2 al and the 3 means there are 3 o
Explanation:
I hope this helps
Three double bonds and four single bonds, or 3(+)+4=7+3, are present in cumulene.
Sigma bond between the hydrogen and carbon on the end-side of the cumulene is visible. Carbon and hydrogen are linked by a total of four sigma bonds. Carbon is joined to carbon in the center by 3 sigma bonds and 3 pi bonds. Cumulene now has a total of 7 sigma bonds and 3 pi bonds. A cumulene is a molecule in organic chemistry that has three or more cumulative (consecutive) double bonds. sp2 hybrid orbital of C overlapping with 2p orbital of O and one bond make up the bond.
In the case of compounds with two bonds, one bond is a sigma bond and the other is a pi bond. A triple bond indicates that the chemicals.
To learn more about bonds please click on below link
brainly.com/question/10777799
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