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netineya [11]
3 years ago
6

Which of the following reactions would be classified as oxidation-reduction? Check all that apply. View Available Hint(s) Check

all that apply. 2Na(s)+Cl2(g)→2NaCl(s) Na(s)+CuCl(aq)→NaCl(aq)+Cu(s) NaCN(aq)+CuCl(aq)→NaCl(aq)+CuCN(s)
Chemistry
1 answer:
erica [24]3 years ago
6 0

Answer:The 1st and 2nd reactions are the example of oxidation -reduction.

Explanation:

Oxidation is basically when a species  loses electrons and  reduction is basically when the species gains  electrons.

A reaction is known as an oxidation -reduction reaction only if  oxidation and reduction simultaneously occur in the reaction. It basically means if a species is getting oxidized in the reaction then the other species present in the system must be reduced in the reaction.

Oxidation-reduction reactions are also known as redox reactions.

In the 1st reaction the oxidation state of Na in reactant is 0 and in products is +1 hence Na is oxidized and the oxidation state of   chlorine is  0 in reactants and  in products is  -1 so chlorine is reduced. Hence Na is oxidized and Cl is reduced so the reaction is a example of oxidation-reduction.

2Na(s)+Cl₂(g)→2NaCl(s)

In the second reaction the oxidation state of Na in reactant is 0 and in products is +1 hence Na is oxidized and the oxidation state of Cu is +1 in reactant and 0 in products so Cu is reduced. Hence Na is oxidized and Cu is reduced so the reaction is an example of oxidation-reduction.

Na(s)+CuCl(aq)→NaCl(aq)+Cu(s)

In the third reaction the oxidation state of Na changes from +1 to +1 and that of Cu also changes from +1 to +1. So there is no change in oxidation state of the species present in reactants and products. Hence this reaction is not an example of oxidation and reduction.

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EastWind [94]

Answer:

1) 90.0 mL

2) 11.25 M

3) 0.477 M

4) 144 mL

Explanation:

The main formula that will be used for all these calculations is:

                                                     C₁V₁ = C₂V₂

C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.

For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.

1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:

5.00 M · V₁ = 500.0mL · 0.900 M                        - divide by 5.00

C₁ = 90.0 mL

2) This time we're finding the initial concentration:

20.0mL · C₁ = 150.0mL · 1.50 M                          - divide by 20.0mL

C₂ = 11.25 M

3) Now we're finding the final concentration:

12.00mL · 3.50 M = 88.0mL · C₂                         - divide by 88.0mL

C₂ = 0.477 M

4) Finally, we're looking for the final volume:

9.0mL · 8.0 M = 0.50 M · V₂                                - divide by 0.50 M

V₂ = 144mL

6 0
3 years ago
B. the aldaric acid of l-idose is the same as the aldaric acid of which sugar?
Artemon [7]
Yes it does because i just read it in a book im pretty sure but idk exactly
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4 years ago
You have collected a tissue specimen that you would like to preserve by freeze drying. To ensure the integrity of the specimen,
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Answer:

The maximum pressure is 612.2 Pa

Explanation:

The pressure of the ice (P1) = 624 Pa

The temperature of the ice = 273.16 K

The maximum temperature the specimen = - 5 oC

                                                                     = -5 + 273 = 268K

The maximum Pressure the freeze drying can be will be (P2) = ?

Using Pressure law, which shows the relationship between pressure and temperature.

                        P1 / T1 = P2 / T2

                       P2 T1 = P1 T2

                       P2 = P1 T2 / T1

                       P2 = 624 × 268 / 273.16

                       P2 = 612.2 Pa

The maximum pressure at which drying can be carried out is 612.2 Pa

Check the attached document more explanation.   jjjjggggg

5 0
4 years ago
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lesya [120]

AMSWER :

CHEMICAL FORMULA :

• WATER - H2O

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2 years ago
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Zolol [24]

Answer:

They are held together by hydrogen bonds

Explanation:

Hydrogen bonds are special dipole-dipole attractions between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom(oxygen or nitorgen or fluorine).

Such molecules includes water, alkanoic acids, ammonia and amines.

A hydrogen nucleus has a high concentration of positive charge. The bond is actually an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom(O or N or F).

Hydrogen bonds are very effective in binding molecules into larger units. Most substances that joins with hydrogen bonds have a higher boiling point and lower volatility.

This is why we have a strong intermolecular bond between water molecules.

5 0
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