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Gala2k [10]
3 years ago
7

What is the molar mass of K?

Chemistry
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

39,0983u. GOOD LESSONS ♡

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How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper
FinnZ [79.3K]

Hope you could understand.

If you have any query, feel free to ask.

3 0
2 years ago
Do you think it matters if you
vovikov84 [41]

Answer:

yes I do think they mean the same thing

Explanation:

150 grams and 150 grams is the same thing and adding 0 to the end of a decimal does not change its value, you could even put 150.0000000 grams and it would still be equivalent to the other numbers

5 0
3 years ago
20 mL of 80°C water is mixed with 20 mL of 0°C water in a perfect calorimeter. What is the final temperature?
dedylja [7]
To calculate for the final temperature, we need to remember that the heat rejected should be equal to the absorbed by the other system. We calculate as follows:

Q1 = Q2
(mCΔT)1 = (mCΔT)2

We can cancel m assuming the two systems are equal in mass. Also, we cancel C since they are the same system. This leaves us,

 (ΔT)1 = (ΔT)2
(T - 80) = (0 - T)
T = 40°C
8 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
inna [77]

Answer:

3.676 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

  • Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

  • Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
4 years ago
Read 2 more answers
Which element has a complete valence electron shell?
borishaifa [10]
Argon, it's a noble gas in the last group on the periodic table.
7 0
3 years ago
Read 2 more answers
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